android - 显示 fragment 点击

Question

我的行有错误

FragmentManager fm = getFragmentManager();

单击时传递 Activity 的任何解决方案？那我需要什么？

public class RecyclerViewAdapter extends RecyclerView.Adapter<RecyclerViewHolders> {

private List<ItemObject> itemList;
private Context context;


public RecyclerViewAdapter(Context context, List<ItemObject> itemList) {
    this.itemList = itemList;
    this.context = context;
}

@Override
public RecyclerViewHolders onCreateViewHolder(ViewGroup parent, int viewType) {

    View layoutView = LayoutInflater.from(parent.getContext()).inflate(R.layout.card_view_list, null);
    RecyclerViewHolders rcv = new RecyclerViewHolders(layoutView);
    return rcv;
}

@Override
public void onBindViewHolder(final RecyclerViewHolders holder, final int position) {
    holder.cardText.setText(itemList.get(position).getName());
    holder.cardPhoto.setImageResource(itemList.get(position).getPhoto());

    holder.itemView.setOnClickListener(new View.OnClickListener() {
        @Override public void onClick(View v) {

            switch (position){
                case 0:

                    FragmentManager fm = getFragmentManager();

                    FragmentTransaction ft = fm.beginTransaction();
                    ft.replace(R.id.frameLayout, new FragmentNewGame(), "newGame");
                    ft.addToBackStack(null);
                    ft.commit();

Answer 1

替换这个:

 FragmentManager fm = getFragmentManager();

为此:

FragmentManager fm = ((Activity)context).getFragmentManager(); 

那么你的代码应该是这样的:

FragmentManager fm = ((Activity)context).getFragmentManager(); 
FragmentTransaction ft = fm.beginTransaction();
ft.replace(R.id.frameLayout, new FragmentNewGame(), "newGame");
ft.addToBackStack(null);
ft.commit();

或者

FragmentTransaction ft = ((Activity)context).getSupportFragmentManager().beginTransaction();
ft.replace(R.id.frameLayout, new FragmentNewGame(), "newGame");
                ft.addToBackStack(null);