android - 如何从 onItemSelectedListener 获取自定义微调器的选定项目位置？

Question

检查下图。我想覆盖方法的 arg2 应该是我当前选择的项目的位置，对吧？但是，它始终为 0。我想要正确的位置来做事。有什么建议吗？

这是我的适配器类。

public class PojoSpinnerAdapter extends ArrayAdapter<Pojo> {

private Activity activty;
private ArrayList<Pojo> pojoList;
LayoutInflater inflater;

public PojoSpinnerAdapter(Activity activity, int resource,
        ArrayList<Pojo> pojoList) {
    super(activity, resource, pojoList);
    this.activty = activity;
    this.pojoList = pojoList;
    inflater = (LayoutInflater) activity
            .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
}

@Override
public View getDropDownView(int position, View convertView, ViewGroup parent) {
    return getCustomView(position, convertView, parent);
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    return getCustomView(position, convertView, parent);
}

public View getCustomView(int position, View convertView, ViewGroup parent) {
    View row = inflater.inflate(R.layout.taxo_spinner_item, parent, false);
    Pojo pojo = pojoList.get(position);

    //.... blah blah
    return row;
} }

Answer 1

我建议不要创建这样的方法并分配 OnItemSelectedListener()。只需像这里这样在类中实现它就可以做到这一点

public class YourClass implements AdapterView.OnItemSelectedListener {}

并将this分配给Spinner，

或

像这里一样匿名尝试

mySpinner = (Spinner) findViewById(R.id.mySpinner);

mySpinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {

        @Override
        public void onItemSelected(AdapterView<?> arg0, View arg1,
                int arg2, long arg3) {

             int selectedPosition = arg2; //Here is your selected position

        }

        @Override
        public void onNothingSelected(AdapterView<?> arg0) {
            // TODO Auto-generated method stub

        }       

    });