android - 为不同的按钮点击打开不同的 Activity

Question

我正在制作一个将点击存储在 firebase 中的投票应用程序。当按下两个按钮中的任何一个时，它应该转到通用布局 Activity (votes.java)。 Btn1 会发生这种情况，但单击 Btn2 时应用会崩溃。

主 Activity .java

import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.ImageView;
import android.os.Handler;
import com.firebase.client.Firebase;
public class Main2Activity extends AppCompatActivity {
private Firebase mRootRef;
private Button mBtn1;
private Button mBtn2;
int counter = 0;
int counter1 = 0;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main2);
    Firebase.setAndroidContext(this);
    mBtn1 = (Button) findViewById(R.id.btn1);
    mBtn2 = (Button) findViewById(R.id.btn2);
    mBtn1.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            if (v.equals(mBtn1)) {
                Intent i1= new Intent(Main2Activity.this, Votes.class);
                startActivity(i1);
                mRootRef = new Firebase("https://voting-cf0fa.firebaseio.com/House/Jupiter/Player 1");
                Firebase mRefChild = mRootRef.child("Votes");
                counter++;
                mRefChild.setValue(counter);

            }

            mRootRef = new Firebase("https://voting-cf0fa.firebaseio.com/House/Jupiter/Player 2");
            mBtn2.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    if (v.equals(mBtn2)) {
                        Intent i2= new Intent(Main2Activity.this, Votes.class);
                        startActivity(i2);
                        Firebase mRefChild = mRootRef.child("Votes");
                        counter1++;
                        mRefChild.setValue(counter1);

                    }
                }

            });
        }
    });

}}

谢谢。

Answer 1

这是因为按钮 2 的点击监听器位于按钮 1 的点击监听器内。您需要为不同的按钮初始化不同的 onClick 监听器。

试试这个:

@Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main2);
        Firebase.setAndroidContext(this);
        mBtn1 = (Button) findViewById(R.id.btn1);
        mBtn2 = (Button) findViewById(R.id.btn2);
        mBtn1.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v)
            {

                Intent i1= new Intent(Main2Activity.this, Voted.class);
                startActivity(i1);
                mRootRef = new Firebase("https://voting-cf0fa.firebaseio.com/House/Jupiter/Player 1");
                Firebase mRefChild = mRootRef.child("Votes");
                counter++;
                mRefChild.setValue(counter);
            });

        mBtn2.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v)
            {
                mRootRef = new Firebase("https://voting-cf0fa.firebaseio.com/House/Jupiter/Player 2");
                Intent i2= new Intent(Main2Activity.this, Voted2.class);
                startActivity(i2);
                Firebase mRefChild = mRootRef.child("Votes");
                counter1++;
                mRefChild.setValue(counter1);
            }
        });