php - mysqli_stmt_execute() 需要 1 个参数，给定 0 个参数

Question

我正在尝试使用准备好的语句方法将 HTML 表单中的数据保存到数据库 wordpress 表:wp_testdb，但是我在 mysqli_stmt_execute( );

Warning: mysqli_stmt_execute() expects exactly 1 parameter, 0 given inHere is my code:

if(isset($_POST['BtnSubmit'])){
    include_once 'dbConnection.php';

    if($conn -> connect_error) {
        die("connection failed:".$conn-> connect_error);
    }
    
    $date           = $_POST['date'];   
    $select_bank    = $_POST['select_bank'];
    $entry_type     = $_POST['entry_type'];
    $income_cat     = $_POST['income_cat'];
    $amount         = $_POST['amount'];
        

    $sql = "INSERT INTO wp_testdb (data_one, data_two, data_three, data_four, data_five) VALUES (?, ?, ?, ?, ?);";
        
    $stmt = mysqli_stmt_init($conn);
        
    if (!mysqli_stmt_prepare($stmt,$sql)) {
            echo "SQL Error !!";
    } else {
        mysqli_stmt_bind_param($stmt, "sssss", $date, $select_bank, $entry_type, $income_cat, $amount);
        mysqli_stmt_execute();
    }
}

dbConnection.php 有以下数据:

<?php

$dbServername = "localhost";    
$dbUsername = "root";
$dbPassword = "";
$dbName = "wordpress";
    
$conn= mysqli_connect($dbServername, $dbUsername, $dbPassword, $dbName);

有什么建议可以解决这个问题吗？

Answer 1

我建议使用面向对象的接口(interface)而不是过程式的。两者都可以工作 - 但是，所有过程函数都需要连接或语句对象作为第一个参数。

根据 documentation ，您需要将语句对象(在您的情况下为 $stmt)作为参数传递。

mysqli_stmt_execute($stmt);

该函数返回一个 bool 值，您可以通过它检查查询是否成功。

if (!mysqli_stmt_prepare($stmt,$sql)) {
        echo "SQL Error !!";
        error_log(mysqli_error($conn));
} else {
    mysqli_stmt_bind_param($stmt, "sssss", $date, $select_bank, $entry_type, $income_cat, $amount);
    if (mysqli_stmt_execute($stmt)) {
        // Query succeeded!
        // Do something
    } else {
        // Query failed. Log it, and do something?
        error_log(mysqli_stmt_error($stmt));
    }
}