javascript - 用于探索大量真/假属性的优雅解决方案

Question

这是一个非常普遍的问题，但我的具体用例是基于包含 true/false 设置的对象构建一个“友好”的过滤器名称。

这是这些设置对象之一的示例

var settings = {
    includeMen: true,
    includeWomen: false,
    includeDependents: true,
}

业余解决方案是一大组 if 语句，例如

if(settings.includeMen && settings.includeWomen && settings.includeDependents){
    return "All People"
}

if(settings.includeMen && !settings.includeWomen && settings.includeDependents){
    return "Men and Children"
}

if(settings.includeMen && settings.includeWomen && !settings.includeDependents){
    return "Men and Women"
}
...

还有什么不那么业余的想法吗？(如果有帮助的话，项目正在使用 Lodash)

Answer 1

 const {includeMen, includeWomen, includeDependents} = settings;

 const result = [];
 if(includeMen) result.push("Men");
 if(includeWomen) result.push("Women");
 if(includeDependents) result.push("Children");

 if(result.length === 3)
   return "All people";
 if(!result.length)
   return "No one";

 return result.join(" and ");

如果您想为每种情况提供自定义输出，您可以进行一些有趣的位移:

const {includeMen, includeWomen, includeDependents} = settings;

return [
 "No one",
 "Children",
 "Women",
 "Children and Women",
 "Men",
 "Men and Children",
 "Men and Women",
"All people"
][+includeDependents + (includeWomen << 1) + (includeMen << 2)];

(免责声明:如果你这样做，你的队友会恨你:))