android - Kotlin 顶层函数 vs 对象函数

Question

我有静态函数，它仅限于某些上下文，例如仅用于文档。有 2 种替代方法可以将其定义为顶级函数或对象中的函数。

1.

package com.armsoft.mtrade.data.pref

import com.armsoft.mtrade.App
import com.armsoft.mtrade.domain.model.DocSaveType

object DocPrefManager {
    private const val DOC_PREF = "DOC_PREF"

    private const val KEY_ORDER_SAVE_TYPE = "KEY_ORDER_SAVE_TYPE"

    @JvmStatic
    fun setOrderSaveType(orderSaveType: DocSaveType) {
        val context = App.getContext()
        val sharedPreferences = context.getSharedPreferences(DOC_PREF, 0)
        val editor = sharedPreferences.edit()
        editor.putString(KEY_ORDER_SAVE_TYPE, orderSaveType.getCode())
        editor.commit()
    }
}

2.

package com.armsoft.mtrade.data.pref

import com.armsoft.mtrade.App
import com.armsoft.mtrade.domain.model.DocSaveType

fun setOrderSaveType(orderSaveType: DocSaveType) {
    val context = App.getContext()
    val sharedPreferences = context.getSharedPreferences(DocPrefManager.DOC_PREF, 0)
    val editor = sharedPreferences.edit()
    editor.putString(DocPrefManager.KEY_ORDER_SAVE_TYPE, orderSaveType.getCode())
    editor.commit()
}

顶级函数的优点是它没有被包装在一个对象中，缺点是它可以在没有类名前缀的情况下从任何地方访问。这种情况有优点或缺点或最佳实践吗？

Answer 1

The recommended practice is to never use object for creating namespaces, and to always use top-level declarations when possible. We haven’t found name conflicts to be an issue, and if you do get a conflict, you can resolve it using an import with alias.