android - 从 onClick 和 onShake 事件中随机生成声音？

Question

我在网上到处找，发现很少说明如何做到这一点。差不多，我在 array.xml 文件中放置了 8 个声音文件，我需要每次或 onClick 或 onShake 播放一次随机选择的文件。首先，我应该使用什么技术来实现这一目标？数组->随机-

STRING->PLAY? RANDOM INT->PLAY? RANDOM INT->STRING->PLAY? Any kind

方向将有很大帮助，因为我将近 3 周的时间对此进行研究。

*注意: MediaPlayer mp = MediaPlayer.create(JelloMan.this, R.原始声音)...我坚持认为您不能用字符串替换“R.raw”部分...

这是完整的代码。

package com.cyphasignals.jelloman;

import java.util.Random;

import android.app.Activity;
import android.hardware.SensorManager;
import android.media.MediaPlayer;
import android.os.Bundle;
import android.view.KeyEvent;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.ImageButton;

public class JelloMan extends Activity {
/** Called when the activity is first created. */

   @Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);        

    private final int NUM_SOUND_FILES = 3;
    //Modifier invalid here 
    private int mfile[] = new mfile[NUM_SOUND_FILES];
    //Modifier invalid here and SECOND "mfile" is wanting to create a class
    private Random rnd = new Random(3);
    //Modifier invalid here 
        mfile[0] = R.raw.sound1;
        mfile[1] = R.raw.sound2;
        mfile[2] = R.raw.sound3;
    int sndToPlay = rnd.nextInt(NUM_SOUND_FILES);

   ShakeListener MyShake = new ShakeListener((SensorManager) 
getSystemService(SENSOR_SERVICE)); 
    MyShake.setForceThreshHold(4.0); 
    MyShake.setOnShakeListener(new ShakeListener.OnShakeListener() {

        MediaPlayer mp = MediaPlayer.create(JelloMan.this, mfile[sndToPlay]);
        //[sndToPlay] wants me to change the modifier
         public void onShake() {
             mp.seekTo(0);
             mp.start();                 
         } 
    });
    ImageButton mouthbutton = (ImageButton)findViewById(R.id.billmouth);
    mouthbutton.setOnClickListener(new OnClickListener() {

        MediaPlayer mp = MediaPlayer.create(JelloMan.this, 
                mfile[sndToPlay]);
            //[sndToPlay] wants me to change the modifier
        public void onClick(View v) {
            mp.seekTo(0);
            mp.start(); 
            }
    });

} 
@Override
public boolean onKeyDown(int keyCode, KeyEvent event)  {

    if (keyCode == KeyEvent.KEYCODE_BACK) {
        finish();
        return true;
    };
    return false;
}

}

Answer 1

半伪代码:

private final int NUM_SOUND_FILES = 3;

private int mSndFiles[] = new int[NUM_SOUND_FILES];
private Random rnd = new Random();   //import java.util.Random for this

mSndFiles[0] = R.raw.sound1;
mSndFiles[1] = R.raw.sound2;
mSndFiles[2] = R.raw.sound3;

int sndToPlay = rnd.nextInt(NUM_SOUND_FILES);

MediaPlayer mp = MediaPlayer.create(JelloMan.this, mSndFiles[sndToPlay]);

如果您拥有的所有声音文件都很小并且您想要低延迟，请考虑使用 SoundPool 而不是 MediaPlayer。

编辑:我并不是要您将上面的代码复制并粘贴到您的应用程序中，我假设您会把东西放在正确的位置。无论如何，试试这个，注意我在代码中的评论。我没有对此进行测试，并假设您还在其他地方定义了“ShakeListener”类，但这应该有效。

package com.cyphasignals.jelloman;

import java.util.Random;
import android.app.Activity;
import android.hardware.SensorManager;
import android.media.MediaPlayer;
import android.os.Bundle;
import android.view.KeyEvent;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.ImageButton;

import com.cyphasignals.R;

public class JelloMan extends Activity {

    private final int NUM_SOUND_FILES = 3;  //*****REPLACE THIS WITH THE ACTUAL NUMBER OF SOUND FILES YOU HAVE*****

    private int mfile[] = new int[NUM_SOUND_FILES];
    private Random rnd = new Random();
    private MediaPlayer mp;

   @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);        

        mfile[0] = R.raw.sound1;  //****REPLACE THESE WITH THE PROPER NAMES OF YOUR SOUND FILES
        mfile[1] = R.raw.sound2;  //PLACE THE SOUND FILES IN THE /res/raw/ FOLDER IN YOUR PROJECT*****
        mfile[2] = R.raw.sound3;

       ShakeListener MyShake = new ShakeListener((SensorManager.getSystemService(SENSOR_SERVICE)); 
       MyShake.setForceThreshHold(4.0); 
       MyShake.setOnShakeListener(new ShakeListener.OnShakeListener() {
          public void onShake() {
             mp = MediaPlayer.create(JelloMan.this, mfile[rnd.nextInt(NUM_SOUND_FILES)]);
             mp.seekTo(0);
             mp.start();                 
       }});

       ImageButton mouthbutton = (ImageButton)findViewById(R.id.billmouth);
       mouthbutton.setOnClickListener(new OnClickListener() {
          public void onClick(View v) {
             mp = MediaPlayer.create(JelloMan.this, mfile[rnd.nextInt(NUM_SOUND_FILES)]);
             mp.seekTo(0);
             mp.start(); 
       }});

   } 
   @Override
   public boolean onKeyDown(int keyCode, KeyEvent event)  {
      if (keyCode == KeyEvent.KEYCODE_BACK) {
         finish();
         return true;
      }
   return false;
   }
}

从结构上讲，您需要考虑如果有人连续摇动设备，它是如何工作的。就像现在一样，它会不断跳回到声音的开头。