mysql - 修复 "Subquery returns more than 1 row"错误

Question

这个问题已经有答案了:

multiple query same table but in different columns mysql (4 个回答)

已关闭 4 年前。

当只有一种类型的分组响应时，我有一个查询准确返回我想要的内容。当有多个时，我收到“子查询返回超过 1 行”错误。

我尝试了多种构造查询的方法，包括使用“in”，但没有任何效果。

SELECT 
    (
    SELECT substring(postcode, 1, locate (' ', postcode) - 1)
    FROM user_locations AS ul
    JOIN users AS u ON u.id = ul.user_id
    WHERE u.membertype = "customer"
    ) AS postcode,
    (
    SELECT count(u.membertype)
    FROM users AS u
    JOIN user_locations AS ul ON u.id = ul.user_id
    WHERE u.membertype = "cook"
    GROUP BY ul.postcode

    ) AS cook,
    (
    SELECT count(u.membertype)
    FROM users AS u
    JOIN user_locations AS ul ON u.id = ul.user_id
    WHERE u.membertype = "customer"
    GROUP BY ul.postcode
    ) AS customer

我希望看到多个邮政编码

Postcode | Cooks | Customers
G83      | 12    | 34 
G84      | 19    | 76
G85      | 10    | 50

Answer 1

您可以使用表达式 u.membertype=xxx 在单个查询中执行此操作，如果 true 则为 1，否则为 0。

SELECT ul.postcode AS "Postcode",
       SUM(u.membertype="cook") as "Cooks"
       SUM(u.membertype="customer") as "Customers"
FROM users AS u
JOIN user_locations AS ul ON u.id = ul.user_id
GROUP BY ul.postcode

如果成员类型超过两种，可以添加WHERE u.membertype IN ("cook","customer")。