gpt4 book ai didi

mysql - 无法在搜索过滤器查询中找到所需的结果

转载 作者:行者123 更新时间:2023-11-29 16:10:35 25 4
gpt4 key购买 nike

我从过去两天开始尝试在查询中获得所需的结果,但无法做到这一点。基本上我正在查询一个餐厅网站“基于标签”的搜索过滤器来搜索最喜欢的菜肴。

有一个单独的标签表,其中根据meal_id、restaurant_id保存了如此多的标签。餐馆->标签和餐点->标签的多对多关系..

用户输入的标签越多,出现的结果就越少。

请查看查询

SELECT
ep_tag.tag_en as tag_meal,
ep_tag2.tag_en as tag_restaurant,
`ep_meal`.id as id_meal,
`ep_meal`.name as name_plat,
`ep_meal`.`id_budget`,
`ep_meal_favorite`.date,
`ep_restaurant`.id as `id_restaurant`,
`ep_restaurant`.*
from
`ep_meal`
inner join
`ep_meal_favorite`
on `ep_meal_favorite`.`id_meal` = `ep_meal`.id
inner join
`ep_restaurant`
on `ep_meal_favorite`.`id_restaurant` = `ep_restaurant`.`id`
inner JOIN
ep_tag
ON ep_meal_favorite.id_meal = ep_tag.id_meal
inner JOIN
ep_tag as ep_tag2
ON ep_meal_favorite.id_restaurant = ep_tag2.id_restaurant
where
ep_meal_favorite.id_epicurean = 82
and `ep_restaurant`.id = 14
and `ep_meal`.id = 92
AND
(
ep_tag.tag_en LIKE '%tuna%'
OR ep_tag2.tag_en LIKE'%tuna%'
)
AND
(
ep_tag.tag_en LIKE '%karaoke%'
OR ep_tag2.tag_en LIKE'%karaoke%'
)

enter image description here

上张图片是当前结果,问题是查询返回记录,其中tag_meal是“tuna”,tag_restaurant是“karaoke”,但匹配时返回空但另一个则不然。

我希望查询在满足一个条件时返回结果假设我为“meal”编写了2个标签,并且没有为“restaurant”编写了标签,反之亦然,同时我希望查询使用 AND,因为我想减少结果数量。

请在这方面帮助我。谢谢。

最佳答案

正如我所评论的,获取与一个或另一个记录匹配的所有行的方法是对它们进行或操作。

SELECT
ep_tag.tag_en as tag_meal,
ep_tag2.tag_en as tag_restaurant,
`ep_meal`.id as id_meal,
`ep_meal`.name as name_plat,
`ep_meal`.`id_budget`,
`ep_meal_favorite`.date,
`ep_restaurant`.id as `id_restaurant`,
`ep_restaurant`.*
from
`ep_meal`
inner join
`ep_meal_favorite`
on `ep_meal_favorite`.`id_meal` = `ep_meal`.id
inner join
`ep_restaurant`
on `ep_meal_favorite`.`id_restaurant` = `ep_restaurant`.`id`
inner JOIN
ep_tag
ON ep_meal_favorite.id_meal = ep_tag.id_meal
inner JOIN
ep_tag as ep_tag2
ON ep_meal_favorite.id_restaurant = ep_tag2.id_restaurant
where
ep_meal_favorite.id_epicurean = 82
and `ep_restaurant`.id = 14
and `ep_meal`.id = 92
AND
(
ep_tag.tag_en LIKE '%tuna%'
OR ep_tag2.tag_en LIKE'%tuna%'
OR ep_tag.tag_en LIKE '%karaoke%'
OR ep_tag2.tag_en LIKE'%karaoke%'
)

这并不是那么有效。您可以构建正则表达式来优化。

关于mysql - 无法在搜索过滤器查询中找到所需的结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55297035/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com