作者热门文章
- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
我有以下语句,但没有结果:
SELECT
temp_manual_pickups.PO,
temp_manual_pickups.INVOICE,
elite_routes.SOURCE,
elite_routes.SOURCE_UDID,
temp_manual_pickups.DESTINATION,
temp_manual_pickups.DESTINATION_UDID,
temp_manual_pickups.DESTINATION_ADDRESS,
temp_manual_pickups.DESTINATION_CITY,
temp_manual_pickups.DESTINATION_STATE,
temp_manual_pickups.DESTINATION_ZIP,
elite_routes.SOURCE AS 'ORDER_BY',
temp_manual_pickups.ZONE,
temp_manual_pickups.PART_NUMBER,
temp_manual_pickups.PART_DESCRIPTION,
temp_manual_pickups.SHIP_TO,
temp_manual_pickups.SHIP_TO_ADDRESS,
temp_manual_pickups.SHIP_TO_CITY,
temp_manual_pickups.SHIP_TO_STATE,
temp_manual_pickups.SHIP_TO_ZIP
FROM
temp_manual_pickups,
elite_routes
WHERE
temp_manual_pickups.zone = elite_routes.route;
如果我运行以下 2 条语句:
SELECT * FROM elite_routes
WHERE ROUTE = 4
结果
route, source, source_udid
4 FBP Doylestown - Main C-Warehouse
和
SELECT * FROM TEMP_MANUAL_PICKUPS
where zone = 4
结果
PO, INVOICE, DESTINATION, DESTINATION_UDID, DESTINATION_ADDRESS, DESTINATION_CITY, DESTINATION_STATE, DESTINATION_ZIP, ZONE, PART_NUMBER, PART_DESCRIPTION, ship_to, ship_to_address, ship_to_city, ship_to_state, ship_to_zip
NEW RETURN-G PU-203151 MAGARITY AUTO Z3422285 7972 ROCKWELL AVE PHILADELPHIA PA 19111-2223 4
68286732AA BRACKET-RADIATOR SUPPORT
NEW RETURN-G PU-203151 MAGARITY AUTO Z3422285 7972 ROCKWELL AVE PHILADELPHIA PA 19111-2223 4
68288334AA BRACKET-SUPPORT FRONT
NEW RETURN-G PU-203151 MAGARITY AUTO Z3422285 7972 ROCKWELL AVE PHILADELPHIA PA 19111-2223 4
68225214AA CLIP-FASCIA
当我单独运行这两个语句时,很明显两个表的相应列中都有“4”,但是当我在 where 子句中比较它们时,我没有得到任何结果。我在某个地方有语法错误吗?
最佳答案
您需要执行 JOIN 来执行连接多个表中数据的查询。
这是带有左连接的查询:
SELECT
temp_manual_pickups.PO,
temp_manual_pickups.INVOICE,
elite_routes.SOURCE,
elite_routes.SOURCE_UDID,
temp_manual_pickups.DESTINATION,
temp_manual_pickups.DESTINATION_UDID,
temp_manual_pickups.DESTINATION_ADDRESS,
temp_manual_pickups.DESTINATION_CITY,
temp_manual_pickups.DESTINATION_STATE,
temp_manual_pickups.DESTINATION_ZIP,
elite_routes.SOURCE AS 'ORDER_BY',
temp_manual_pickups.ZONE,
temp_manual_pickups.PART_NUMBER,
temp_manual_pickups.PART_DESCRIPTION,
temp_manual_pickups.SHIP_TO,
temp_manual_pickups.SHIP_TO_ADDRESS,
temp_manual_pickups.SHIP_TO_CITY,
temp_manual_pickups.SHIP_TO_STATE,
temp_manual_pickups.SHIP_TO_ZIP
FROM
temp_manual_pickups
LEFT JOIN
elite_routes
ON
temp_manual_pickups.zone = elite_routes.route;
关于mysql - 使用 Where 子句比较 2 个表中的列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55299388/
我是一名优秀的程序员,十分优秀!