javascript - GraphQL 无法解析嵌套对象属性

Question

我正在尝试返回一个带有列表中一些嵌套属性对象的 graphQL 查询。一切似乎都已检查完毕，但我得到的是空值。

预期的数据结构响应(有关结构的更多详细信息 here ):

//Return a GraphQLList type of all objects :    
[
    {
        "subscription" : {

        },
        "customer" : {

        },
    },
]

查询:{ subscriptions { subscription { id customer_id } } }

GraphQL 查询对象:

var Query = new graphQL.GraphQLObjectType({
    name: 'Query',
    description: 'Root of the Schema',
    fields: {
        subscriptions: {
            type: new graphQL.GraphQLList(SubscriptionsList),
            args : {
                customer_name: { type: graphQL.GraphQLString },
                customer_id: { type: graphQL.GraphQLString }
            },
            resolve : function (source, args) {
                return getSubscriptions().then(function (res) {
                    // Shows that data is returned
                    console.log('Data: ', res.list);

                    return res.list;
                }).catch(function (err) {
                    return err;
                });
            }
        }
    }
});

它期望返回 SubscriptionsList 的 GraphQLList 类型:

var SubscriptionsList = new graphQL.GraphQLObjectType({
    name : 'SubscriptionObj',
    description : 'stuff',
    fields : function () {
        return {
            subscription : {
                type : Subscription,
                resolve : function (subscription) {
                    return  subscription;
                }
            }
        }
    }
});

应该解析嵌套字段属性:

var Subscription = new graphQL.GraphQLObjectType({
    name : 'Subscription',
    description : 'stuff',
    fields : function () {
        return {
            id: {type: graphQL.GraphQLString},
            customer_id: {type: graphQL.GraphQLString}
        }
    }
});

Console.log(res.list) 输出(来自查询):我确实得到了我期望的数据和结构:

[ { subscription: 
     { id: 'cbdemo_lloyd-sub2',
       customer_id: 'cbdemo_lloyd',
       plan_id: 'cbdemo_nuts',
       addons: [Object],
       due_invoices_count: 0,
       shipping_address: [Object] },
    customer: {
       ...
    }
  },
  {...}
]

GraphQL 查询输出:

{
  "data": {
    "subscriptions": [
      {
        "subscription": {
          "id": null,
          "customer_id": null
        }
      },
      {
        "subscription": {
          "id": null,
          "customer_id": null
        }
      },

---

编辑 不是真的有必要，但这是返回 promise 的 getSubscriptions() API 调用:

function getSubscriptions() {
    return new Promise(function (resolve, reject) {
        chargebee.subscription.list({
            limit : 5,
            "plan_id[is_not]" : "basic",
            "status[is]" : "active",
            "sort_by[asc]" : "created_at"
        }).request(function(error,result){
            if (error) return reject(error);
            return resolve(result);
        });
    });
}

Answer 1

看起来你有点困惑，基本上，当你设置

new graphQL.GraphQLList(SubscriptionsList),

这已经是一个列表。这意味着你真正的意思是

new graphQL.GraphQLList(Subscription),

接下来，您的订阅对象不包含任何解析逻辑，所以我希望它是这样的:

var Subscription = new graphQL.GraphQLObjectType({
    name : 'Subscription',
    description : 'stuff',
    fields : function () {
        return {
            id: {
                   type: graphQL.GraphQLString,
                   resolve: function(subscription) {
                       return subscription.subscription.id;
                   }
            },
            customer_id: {
                   type: graphQL.GraphQLString,
                   resolve: function(subscription) {
                       return subscription.subscription.customer_id;
                   }
            },
        }
    }
});

在幕后基本上发生的事情是，GraphQL 将使用 Subscription 对象解析提供的列表中的每个 javascript 对象。那里的每个解析器都会将 javascript 对象作为第一个值，并从中返回基本值。