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mysql - 使用 SUM 和 JOIN 查询发现意外的 SUM 结果

转载 作者:行者123 更新时间:2023-11-29 16:00:09 25 4
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我有两个表“tbl_orders”和“tbl_instore”。 tbl_orders 有“sel_product_qty”,我想按日期进行 SUM,表(tbl_instore)有“inst_prod_qty”和“chln_amount”,我计算并希望获得购买的单价。但是,当我对这两个表使用联接查询时,SUM(sel_product_qty) 会产生预期结果的两倍、三倍和四倍的金额。

示例数据表是..

表“tbl_order”:

+----------+------------+------------+-----------------+---------------+--------------------+
| order_id | ord_det_id | product_id | sel_product_qty | selling_price | order_date_time |
+----------+------------+------------+-----------------+---------------+--------------------+
| 3 | 1 | 4 | 50 | 67.82 | 2019-03-21 21:52:21|
| 4 | 1 | 1 | 100 | 37.88 | 2019-03-21 21:52:21|
| 5 | 2 | 4 | 120 | 67.82 | 2018-03-23 00:02:36|
| 6 | 3 | 3 | 300 | 123.67 | 2019-03-23 00:04:38|
| 7 | 3 | 2 | 50 | 76.28 | 2019-03-23 00:04:38|
| 8 | 4 | 4 | 50 | 67.82 | 2019-03-24 12:13:06|
| 9 | 4 | 2 | 100 | 76.28 | 2019-03-24 12:13:06|
| 10 | 5 | 1 | 10 | 37.88 | 2019-03-25 12:56:40|
| 11 | 5 | 4 | 7 | 67.82 | 2019-03-25 12:56:40|
| 12 | 6 | 4 | 23 | 67.82 | 2019-03-29 00:29:14|
| 13 | 6 | 2 | 25 | 76.28 | 2019-03-29 00:29:14|
| 16 | 7 | 1 | 120 | 37.88 | 2019-04-14 16:51:10|
| 17 | 7 | 3 | 90 | 123.67 | 2019-04-14 16:51:11|
| 18 | 8 | 1 | 100 | 66.95 | 2019-04-22 23:30:39|
| 19 | 8 | 2 | 22 | 70.04 | 2019-04-22 23:30:39|
+----------+------------+------------+-----------------+---------------+--------------------+

表“tbl_instore”:

+----------+----------+------------+---------------+-------------+--------------------+
| in_st_id | s_inv_id | product_id | inst_prod_qty | chln_amount | instore_date_time |
+----------+----------+------------+---------------+-------------+--------------------+
| 1 | 1 | 1 | 1000 | 65852 | 2/14/2018 17:28 |
| 14 | 9 | 1 | 100 | 6400 | 4/26/2019 8:26 |
| 3 | 2 | 1 | 2000 | 58885 | 3/19/2019 17:32 |
| 5 | 3 | 1 | 100 | 3588 | 3/19/2019 17:35 |
| 11 | 7 | 1 | 1000 | 65000 | 4/22/2019 23:17 |
| 9 | 5 | 1 | 100 | 6345 | 4/20/2019 0:13 |
| 12 | 8 | 2 | 100 | 7800 | 4/22/2019 23:20 |
| 8 | 4 | 2 | 2000 | 144567 | 3/23/2019 0:04 |
| 7 | 4 | 3 | 1000 | 121665 | 3/23/2019 0:04 |
| 13 | 8 | 3 | 150 | 32000 | 4/22/2019 23:20 |
| 15 | 9 | 3 | 100 | 19000 | 4/26/2019 8:26 |
| 10 | 6 | 4 | 1000 | 88022 | 4/20/2019 0:16 |
| 6 | 3 | 4 | 100 | 6582 | 3/19/2019 17:35 |
| 4 | 2 | 4 | 1000 | 65882 | 3/19/2019 17:32 |
| 2 | 1 | 4 | 5000 | 359877 | 2/14/2018 17:28 |
+----------+----------+------------+---------------+-------------+--------------------+

我当前尝试过以下查询:

SELECT SUM(tbl_orders.sel_product_qty) AS `sel_prod_qty`,
(SUM(chln_amount) / SUM(inst_prod_qty)) AS `pur_uni_price`,
date_format(`order_date_time`, '%M-%Y') as `month`,
tbl_orders.product_id AS `product_id`
FROM tbl_orders
INNER JOIN tbl_instore ON tbl_instore.product_id = tbl_orders.product_id
WHERE YEAR(`order_date_time`)= '2019'
GROUP BY `month`, `product_id`;

返回以下结果:

+--------------+---------------+--------+------------+
| sel_prod_qty | pur_uni_price | month | product_id |
+--------------+---------------+--------+------------+
| 1320 | 47.923256 | Apr-19 | 1 |
+--------------+---------------+--------+------------+
| 44 | 72.555714 | Apr-19 | 2 |
+--------------+---------------+--------+------------+
| 270 | 138.132 | Apr-19 | 3 |
+--------------+---------------+--------+------------+
| 660 | 47.923256 | Mar-19 | 1 |
+--------------+---------------+--------+------------+
| 350 | 72.555714 | Mar-19 | 2 |
+--------------+---------------+--------+------------+
| 900 | 138.132 | Mar-19 | 3 |
+--------------+---------------+--------+------------+
| 520 | 73.290563 | Mar-19 | 4 |
+--------------+---------------+--------+------------+

如果我在没有 JOIN 的情况下单独运行查询,我将得到如下 SUM(sel_prod_qty) 值(我的预期结果也应该是):

+--------------+---------------+--------+------------+
| sel_prod_qty | pur_uni_price | month | product_id |
+--------------+---------------+--------+------------+
| 220 | 47.923256 | Apr-19 | 1 |
+--------------+---------------+--------+------------+
| 22 | 72.555714 | Apr-19 | 2 |
+--------------+---------------+--------+------------+
| 90 | 138.132 | Apr-19 | 3 |
+--------------+---------------+--------+------------+
| 110 | 47.923256 | Mar-19 | 1 |
+--------------+---------------+--------+------------+
| 175 | 72.555714 | Mar-19 | 2 |
+--------------+---------------+--------+------------+
| 300 | 138.132 | Mar-19 | 3 |
+--------------+---------------+--------+------------+
| 130 | 73.290563 | Mar-19 | 4 |
+--------------+---------------+--------+------------+

所以,我的问题是,为什么我的查询返回的 SUM(sel_product_qty) 数量是预期结果的两倍、三倍和四倍?

最佳答案

试试这个:

SELECT `sel_prod_qty`,
`pur_uni_price`,
`month`,
orders.product_id AS `product_id`
FROM
(SELECT product_id,SUM(sel_product_qty) AS `sel_prod_qty`,
DATE_FORMAT(`order_date_time`, '%M-%Y') AS `month`
FROM tbl_orders
WHERE YEAR(`order_date_time`)='2019'
GROUP BY `month`, `product_id`) orders
INNER JOIN
(SELECT product_id,(SUM(chln_amount) / SUM(inst_prod_qty)) AS `pur_uni_price`
FROM tbl_instore GROUP BY product_id) instore
ON orders.product_id=instore.product_id;

我从您加入的那些表中创建了两个子查询,因为不起作用的是您正在执行INNER JOIN ... ON tbl_instore.product_id = tbl_orders.product_id。如果您回顾一下您的表,这些值在两个表中都重复了多次。因此,该子查询将执行数学运算,而外部查询将仅返回其结果。

关于mysql - 使用 SUM 和 JOIN 查询发现意外的 SUM 结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56250916/

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