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mysql - 如何解决使用 hibernate 5 和 mysql 出现 HHH000346 错误?

转载 作者:行者123 更新时间:2023-11-29 16:00:06 26 4
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我正在研究安心的服务和观点。关于它,我使用mysql和hibernate 5。我的数据表有两个,有引用关系。当我更新主键时出现问题。当我添加新数据然后更新另一表中的现有数据(它们具有引用关系)时,HHH000346:托管刷新期间发生错误。

我已经在 google 上搜索过,但找不到答案。

这是我的实体类。

@Entity
@Table(name = "users")
@EntityListeners(AuditingEntityListener.class)
public class User {
private long serial;
private String username;
private String password;

public User() {

}

public User(long serial, String username, String password) {
setSerial(serial);
setUsername(username);
setPassword(password);
}

@Column(name = "serial", nullable = false)
@GeneratedValue(strategy = GenerationType.AUTO)
public long getSerial() {
return serial;
}

public void setSerial(long serial) {
this.serial = serial;
}

@Id
public String getUsername() {
return username;
}

public void setUsername(String username) {
this.username = username;
}

@Column(name = "password", nullable = false)
public String getPassword() {
return password;
}

public void setPassword(String password) {
this.password = password;
}

@Override
public String toString() {
return "serial: " + this.serial + ", username: " + this.username + ", password: " + this.password;
}
}
Entity
@Table(name = "sites")
@EntityListeners(AuditingEntityListener.class)
@IdClass(Site.class)
public class Site implements Serializable{
@ManyToOne
@JoinColumn(name="username",foreignKey=@ForeignKey(name="username"))
private String username;
private String siteURL;

@Id
public String getUsername() {
return username;
}

public void setUsername(String username) {
this.username = username;
}

@Id
public String getSiteURL() {
return siteURL;
}

public void setSiteURL(String siteName) {
this.siteURL = siteName;
}
}

这是类有问题的。

public class UserController {

@Autowired
private UserRepository userRepository;
@Autowired
private SiteRepository siteRepository;
private CryptoUtil passwordEncoder = new CryptoUtil();

...

@PutMapping("/users/{username}")
public User updateUser(@PathVariable(value = "username") String username, @Valid @RequestBody User userDetails)
throws ResourceNotFoundException {
User user = userRepository.findById(username)
.orElseThrow(() -> new ResourceNotFoundException("User not found on :: " + username));
List<Site> sites = siteRepository.findByUsername(user.getUsername());

userDetails.setPassword(passwordEncoder.encryptSHA256(userDetails.getPassword()));
final User updateUser = userRepository.save(userDetails);

for (Site site : sites)
{
site.setUsername(userDetails.getUsername());
site = siteRepository.save(site);
}

userRepository.delete(user);
return updateUser;
}

....
}
The for-each statement occurs error.

PLEASE HELP ME

最佳答案

你为什么这么做?

@ManyToOne
@JoinColumn(name="username",foreignKey=@ForeignKey(name="username"))
private String username;

应该是:

@ManyToOne
@JoinColumn(name="username",foreignKey=@ForeignKey(name="username"))
private User user;

我还建议您使用主键作为外键。并且一个实体中不能有多个 @Id

关于mysql - 如何解决使用 hibernate 5 和 mysql 出现 HHH000346 错误?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56253921/

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