gpt4 book ai didi

PHP 通过单击查看按钮查看单个记录中的数据

转载 作者:行者123 更新时间:2023-11-29 15:59:56 25 4
gpt4 key购买 nike

我有两个页面 Students_list.php 和 Students_profile.php

在students_list.php上,我有一个表格,显示所有学生的所有记录和“查看”按钮,单击该按钮应打开students_profile.php页面,并从基于std_id选择的单个记录中获取所有数据

更新:所以现在我得到了 id http://localhost/sms/student_profiles.php?std_id=3当我单击“查看”按钮但我仍然无法从所选的该记录中检索数据

这是students_list.php的代码

<?php
require_once 'include/database/connect.php';

try {
$pdo = new PDO("mysql:host=$host_db;dbname=$name_db", $user_db, $pass_db);
$sql = 'SELECT * FROM students';
$q = $pdo->query($sql);
$q->setFetchMode(PDO::FETCH_ASSOC);
} catch (PDOException $e) {
die("Could not connect to the database $name_db :" . $e->getMessage());
}
?>
<table id="data-table-default" class="table">
<thead>
<tr>
<th width="1%">#</th>
<th width="1%" data-orderable="false"></th>
<th>Name & Surname</th>
<th>Gender</th>
<th>Faculty</th>
<th>Semester</th>
<th>Mobile</th>
<th></th>
</tr>
</thead>

<tbody>
<?php while ($row = $q->fetch()): ?>
<tr class="odd gradeX">
<td width="1%" class="f-s-600 text-inverse"><?php echo ($row['std_id']) ?></td>
<td width="1%" class="with-img"><?php echo ($row['std_status']) ?></td>
<td><?php echo ($row['std_name']) ?></td>
<td><?php echo ($row['std_gender']) ?></td>
<td><?php echo ($row['std_faculty']) ?></td>
<td><?php echo ($row['std_semester']) ?></td>
<td><?php echo ($row['std_mobile']) ?></td>
<td align="right">
<a href="student_profiles.php?std_id=<?php echo $row['std_id']; ?>" class="btn btn-warning btn-xs"><i class="fas fa-eye"></i> View</a>
</td>
</tr>
<?php endwhile; ?>
</tbody>
</table>

下面是student_profile.php

<?php
require_once('include/database/sharepoint.php');
if(isset($_GET) & !empty($_GET)){
$std_id = $_GET['std_id'];
$sql = "SELECT * FROM `students` WHERE std_id=$std_id";
$res = mysqli_query($connection, $sql);
}
?>

<h4><?php echo ($row['std_name']) ?></h4>

<div class="d-flex">
<div class="pr-4"><strong>NATIONAL#</strong> <?php echo ($row['std_number']) ?></div>
<div class="pr-4"><strong>DOB</strong> <?php echo ($row['std_dob']) ?></div>
<div class="pr-4"><strong>GENDER</strong> <?php echo ($row['std_gender']) ?></div>
<div class="pr-4"><strong>MOBILE</strong> <?php echo ($row['std_mobile']) ?></div>
</div>
<div class="pt-1 font-weight-bold">Master's Degree (MBA)</div>
<div>STD# <strong><?php echo ($row['std_id']) ?></strong></div>
<div><a href="#" target="new">email@example.com</a></div>

最佳答案

您没有从查询中获取数据。所以 $row 永远不会包含您期望的数组:

$row = mysqli_fetch_assoc($res); //this will populate $row

在您的代码中:

<?php
require_once('include/database/sharepoint.php');
if(isset($_GET) & !empty($_GET)){
$std_id = $_GET['std_id'];
$sql = "SELECT * FROM `students` WHERE std_id=$std_id";
$res = mysqli_query($connection, $sql);
$row = mysqli_fetch_assoc($res);
}
?>

关于PHP 通过单击查看按钮查看单个记录中的数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56262519/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com