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mysql - 如何将关系代数除法转换为sql除法查询?

转载 作者:行者123 更新时间:2023-11-29 15:52:15 25 4
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表格:

Flights(Flno, Origin, Destination, Distance, departs, Arrives) <br>
Flight Instance(Flno, Day, Aid)<br>
Aircraft(Aid, Make, Model, CrusingRange)<br>
Certied(Eid, Make, Model)<br>
Employee(Eid, Ename, Salary)<br>
Fight Attendant(Flno, Day, Eid, Role)<br> <br>

我知道如何用关系代数来写它:

∏Eid,目的地(σeid,目的地(Flight_Attendant flno=flno * 航类))/∏目的地(σDestination(航类))

如何在 sql 中转换它?所以结果将是去过所有城市的员工列表。

最佳答案

也许是这样的:

SET @TotalDestinations = (SELECT COUNT(AUX.Destination) FROM
(select distinct Destination from Flights) AS AUX);

SELECT A.eid, Employee.Ename -- select only those who traveled to all destinations
FROM
(
-- know all the destinations for all assistant
SELECT DISTINCT Flight_attendant.eid, Flights.Destination
FROM Flight_attendant
INNER JOIN Flights ON Flight_attendant.flno=Flights.flno
) AS A
INNER JOIN Employee ON Employee.Eid = A.Eid
GROUP BY A.eid, Employee.Ename
HAVING COUNT(*) = @TotalDestinations

关于mysql - 如何将关系代数除法转换为sql除法查询?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56707550/

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