android - 在 OneSignal 中打开通知点击应用程序

Question

我通过 OneSignal 收到通知，但我想在单击通知时打开应用程序

private static class ExampleNotificationOpenedHandler implements OneSignal.NotificationOpenedHandler {
    @Override
    public void notificationOpened(String message, JSONObject additionalData, boolean isActive) {

        try {
            if (additionalData != null) {
                if (additionalData.has("actionSelected"))
                    Log.d("OneSignalExample", "OneSignal notification button with id " + additionalData.getString("actionSelected") + " pressed");
                Log.d("OneSignalExample", "Full additionalData:\n" + additionalData.toString());
            }
        } catch (Throwable t) {
            t.printStackTrace();
        }

Answer 1

在 ExampleNotificationOpenedHandler 中添加一个将上下文作为参数的构造函数

private Context mContext;

public ExampleNotificationOpenedHandler(Context context) {
    mContext = context;
}

使用ExampleNotificationOpenedHandler 构造函数初始化OneSignal，在应用程序类中包含上下文

public void onCreate() {
    super.onCreate();
    OneSignal.startInit(this)
             .setNotificationOpenedHandler((OneSignal.NotificationOpenedHandler)
                        new ExampleNotificationOpenedHandler(this))
             .init();
}

准备 Intent 并使用上下文开始您的 Activity

@Override
public void notificationOpened(OSNotificationOpenResult result) {
    try {
        if (additionalData != null) {
            Intent intent = new Intent(mContext, DetailsActivity.class);
            intent.setFlags(Intent.FLAG_ACTIVITY_REORDER_TO_FRONT | Intent.FLAG_ACTIVITY_NEW_TASK);
            intent.putExtra("key", <additionalData to be sent>);
            mContext.startActivity(intent);
    }
} catch (Throwable t) {
    t.printStackTrace();
}