mysql - Laravel-从下拉列表中选择值后自动填充输入

Question

选择下拉列表后如何进行自动填充。我不太擅长 js 或 ajax。当用户选择 doc_no 时，必须填写 rev_no 和 title 字段。谢谢!

查看

 <div class="form-group">
{!! Form::label('text', 'Doc No', ['class' => 'col-lg-3 control-label']) !!}
<div class="col-lg-10">
<select name="docNo" id="docNo" class="form-control" style="width:250px">

@foreach ($soplists as $soplist)
<option value="{{ $soplist->id }}">{{ $soplist->doc_no }}</option>
@endforeach
</select>
</div>
</div>



<input type="hidden" name="carType" value="Internal Audit" class="form-control">

<div class="form-group">
{!! Form::label('text', "Rev No", ['class' => 'col-lg-5 control-label']) !!}
<div class="col-lg-5">
<input type="text" class="form-control" id="rev" />

</div>
</div>


<div class="form-group">
{!! Form::label('text', "Title", ['class' => 'col-lg-5 control-label']) !!}
<div class="col-lg-10">
<input type="text" class="form-control" id="title" />

</div>

<script>
    $('#docNo').change(function() {
        var id = $(this).val();
        var url = '{{ route("getDetails", ":id") }}';
        url = url.replace(':id', id);

        $.ajax({
            url: url,
            type: 'get',
            dataType: 'json',
            success: function(response) {
                if (response != null) {
                    $('#rev').val(response.rev_no);
                    $('#title').val(response.title);
                }
            }
        });
    });
</script>

Controller ---php

   public function getDetails($id = 0)
{
    $data = sopList::where('doc_no', $id)->first();
    echo json_encode($data);
    exit;
}

<小时/>

路线

'Route::get('get/details/{id}', 'internalAuditController@getDetails')->name('getDetails');'

数据库sop_list表图片链接

https://ibb.co/SwkJhLc

下拉菜单和输入图像

https://ibb.co/0VN3Z2y

网络选项卡

https://ibb.co/56w5BLD

Answer 1

在web.php文件中添加路由:

Route::get('get/details/{id}', 'YourController@getDetails')->name('getDetails');

Controller 功能:

public function getDetails($id = 0)
{
    $data = sopList::where('doc_no',$id)->first();
    return response()->json($data);
}

并查看脚本:

$('#docNo').change(function(){
    var id = $(this).val();
    var url = '{{ route("getDetails", ":id") }}';
    url = url.replace(':id', id);

    $.ajax({
        url: url,
        type: 'get',
        dataType: 'json',
        success: function(response){
            if(response != null){
                $('#rev').val(response.rev_no);
                $('#title').val(response.title);
            }
        }
    });
});

Make sure to add the id rev and title to the rev and title input fields respectively.