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php - 使用 php 和单选按钮更新数据

转载 作者:行者123 更新时间:2023-11-29 15:32:27 26 4
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我的表单似乎没有更新。它只是忽略了 php 代码。我用不同的形式使用相同的 php 代码,从来没有遇到过任何问题。我不知道是否是这样,因为我现在使用单选按钮。

if (isset($_POST['submitinjury'])) {
$query = "UPDATE injury SET neck=?,
upperback=?,
lowerback=?,
chest=?,
shoulder=?,
arm=?,
hand=? WHERE userid=?";
$stmt = mysqli_prepare($db, $query);
mysqli_stmt_bind_param($stmt, 'ssssssss', $_POST['neck'], $_POST['upperback'], $_POST['lowerback'], $_POST['chest'], $_POST['shoulder'], $_POST['arm'], $_POST['hand'], $_SESSION['id']);
mysqli_stmt_execute($stmt);
exit(header('location: home.php'));
}

表格。这是在 new.php 文件中。

<form action="new.php"  method="post"   >
<table>
<tr>
<th style="font-size:18px" >Any previous injuries y</th>
</tr>
<tr>
<td>Previous neck injury/surgery?</td>
<td></td>
<td></td>
<td><label class="container">Yes
<input type="radio" name="neck" value="yes" >
<span class="checkmark"></span>
</label></td>
<td><label class="container">None
<input value="none" type="radio" checked="checked" name="neck">
<span class="checkmark"></span>
</label></td>
</tr>
<tr>

<td>Previous upperback injury/surgery?</td>
<td></td>
<td></td>
<td><label class="container">Yes
<input type="radio" name="upperback" value="yes" >
<span class="checkmark"></span>
</label></td>
<td><label class="container">None
<input value="none" type="radio" checked="checked" name="upperback">
<span class="checkmark"></span>
</label></td>
</tr>
<tr>
<td>Previous lowerback injury/surgery?</td>
<td></td>
<td></td>
<td><label class="container">Yes
<input type="radio" name="lowerback" value="yes" >
<span class="checkmark"></span>
</label></td>
<td><label class="container">None
<input value="none" type="radio" checked="checked" name="lowerback">
<span class="checkmark"></span>
</label></td>
</tr>
<tr>
<td>Previous chest injury/surgery?</td>
<td></td>
<td></td>
<td><label class="container">Yes
<input type="radio" name="chest" value="yes" >
<span class="checkmark"></span>
</label></td>
<td><label class="container">None
<input value="none" type="radio" checked="checked" name="chest">
<span class="checkmark"></span>
</label></td>
</tr>


<tr>
<td>Previous shoulder injury/surgery?</td>
<td><label class="container">Both
<input value="both" type="radio" name="shoulder">
<span class="checkmark"></span>
</label></td>
<td><label class="container">Left
<input value="left" type="radio" name="shoulder">
<span class="checkmark"></span>
</label></td>
<td><label class="container">Right
<input value="right" type="radio" name="shoulder">
<span class="checkmark"></span>
</label></td>
<td><label class="container">None
<input value="none" type="radio" checked="checked" name="shoulder">
<span class="checkmark"></span>
</label></td>
</tr>
<tr>
<td>Previous arm injury/surgery?</td>
<td><label class="container">Both
<input value="both" type="radio" name="arm">
<span class="checkmark"></span>
</label></td>
<td><label class="container">Left
<input value="left" type="radio" name="arm">
<span class="checkmark"></span>
</label></td>
<td><label class="container">Right
<input value="right" type="radio" name="arm">
<span class="checkmark"></span>
</label></td>
<td><label class="container">None
<input type="radio" checked="checked" value="none" name="arm">
<span class="checkmark"></span>
</label></td>
</tr>
<tr>
<td>Previous hand/wrist injury/surgery?</td>
<td><label class="container">Both
<input value="both" type="radio" name="hand">
<span class="checkmark"></span>
</label></td>
<td><label class="container">Left
<input value="left" type="radio" name="hand">
<span class="checkmark"></span>
</label></td>
<td><label class="container">Right
<input value="right" type="radio" name="hand">
<span class="checkmark"></span>
</label></td>
<td><label class="container">None
<input type="radio" checked="checked" value="none" name="hand">
<span class="checkmark"></span>
</label></td>
</tr>


</table>

<button type="submit" name="submitinjury" >Submit</button>

</form>

单击按钮后,它只会刷新页面,数据库中不会更新任何内容。

最佳答案

看来,问题是由 session 引起的。尝试添加 session_start()

if (isset($_POST['submitinjury'])) {
session_start();
$query = "UPDATE injury SET neck=?,
upperback=?,
lowerback=?,
chest=?,
shoulder=?,
arm=?,
hand=? WHERE userid=?";
$stmt = mysqli_prepare($db, $query);
mysqli_stmt_bind_param($stmt, 'ssssssss', $_POST['neck'], $_POST['upperback'], $_POST['lowerback'], $_POST['chest'], $_POST['shoulder'], $_POST['arm'], $_POST['hand'], $_SESSION['id']);
mysqli_stmt_execute($stmt);
exit(header('location: home.php'));
}

关于php - 使用 php 和单选按钮更新数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58585944/

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