php - json_encode (PHP) + JSON_ARRAYAGG (mySQL) 中的反斜杠

Question

问题是数组颜色中带有引号的反斜杠。我认为这是因为 JSON_ARRAYAGG 但我不知道如何打印正确的 json。

查询:

SELECT a.id_product, JSON_ARRAYAGG(c.name_color) as colors, a.url 
FROM products as a 
LEFT JOIN product_has_colors b ON a.id_product = b.id_product 
LEFT JOIN colors c ON c.id_color = b.id_color 
GROUP BY a.id_product;

+------------+-------------------+-----------------+
| id_product | colors            | url             |
|------------+-------------------+-----------------+
|     1      | ["yellow", "blue"]| https://url.com |
|     2      | ["black, "green"] | https://url.com |
+------------+-------------------+-----------------+

PHP:

header('Content-Type: application/json);
echo json_encode($data, JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES | JSON_PRETTY_PRINT);

输出:

[
  {
    "id_product: "1",
    "colors": [\"yellow\", \"blue\"]",
    "url": "https://url.com"
  },
 {
    "id_product: "2",
    "colors": [\"black\", \"green\"]",
    "url": "https://url.com"
  }
]

Answer 1

您正在对颜色进行两次编码。首先使用 SQL，然后使用 PHP。您可以做的是在编码 $data 之前在 PHP 中解码 colors:

foreach ($data as $key = $row) {
    $data[$key]['colors'] = json_decode($row['colors']);
}

如果您作为对象获取，则使用:

foreach ($data as $obj) {
    $obj->colors = json_decode($obj->colors);
}

或者完全用 SQL 生成 JSON:

SELECT JSON_ARRAYAGG(JSON_OBJECT(
    'id_product', id_product,
    'colors', colors,
    'url', url
)) as json
FROM (
    SELECT a.id_product, JSON_ARRAYAGG(c.name_color) as colors, a.url 
    FROM products as a 
    LEFT JOIN product_has_colors b ON a.id_product = b.id_product 
    LEFT JOIN colors c ON c.id_color = b.id_color 
    GROUP BY a.id_product
) x