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javascript - 将多个 div 拖入另一个 jQuery

转载 作者:行者123 更新时间:2023-11-29 15:12:13 26 4
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我一直在尝试使用 jQuery 将 div 从一个 div 拖到另一个。这是我到目前为止所得到的

$(document).ready(function() {
$(".draggable").draggable();
$(".bucket").droppable({
drop: function(event, ui) {
if (($(this).attr('id')) !== ui.draggable.attr("data-bucket")) {
ui.draggable.attr("data-bucket", $(this).attr('id'));

var p1 = ui.draggable.parent().offset();
$(this).append(ui.draggable);

var p2 = ui.draggable.parent().offset();

ui.draggable.css({
top: parseInt(ui.draggable.css('top')) + (p1.top - p2.top),
left: parseInt(ui.draggable.css('left')) + (p1.left - p2.left)
});
}
}
});
});
.bucket {
width: 400px;
height: 150px;
background: #ddd
}

.draggable {
width: 50px;
height: 30px;
margin-top: 5px;
background: red;
}

#destination {
background: #aaa
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://code.jquery.com/ui/1.12.0/jquery-ui.min.js"></script>
<div class="bucket" id="origin">
<div class="draggable" data-bucket="origin">Drop 1</div>
<div class="draggable" data-bucket="origin">Drop 2</div>
<div class="draggable" data-bucket="origin">Drop 3</div>
<div class="draggable" data-bucket="origin">Drop 4</div>
</div>
<div class="bucket" id="destination">
</div>

我已经从this 改编了js答案,但为了处理多个可拖动元素,我使用了 data-bucket 属性仅在元素最初放入桶中时应用定位,而不是每次在其中移动时应用定位。

正如您从示例中看到的那样,这种解决方案是可行的,但是一旦将两个以上的 div 拖入目标桶中,它们就会开始跳来跳去,不会落在光标放置它们的位置

这似乎应该是一个简单的修复,但我已经为这个问题摸不着头脑了一天左右,有什么帮助吗?

最佳答案

我已将 .draggable div CSS 设置为 position: absolute,并将父元素设置为 position: relative。还有一些调整,用于初始显示绝对定位的 div 并在它们被删除后显示状态。

请看下面的代码:

    $(document).ready(function () {
$.each( $(".draggable"), function( key, value ) {
$(this).css('top',(35*key)+"px");
});
$(".draggable").mousedown(function() {
$("#status").html('');
})

$(".draggable").draggable();
$(".bucket").droppable({
drop: function (event, ui) {
$("#status").html(ui.draggable.html()+" is in the "+$(this).attr('id')+" bucket.");

if (($(this).attr('id')) !== ui.draggable.attr("data-bucket")) {
ui.draggable.attr("data-bucket", $(this).attr('id'));

var p1 = ui.draggable.parent().offset();
$(this).append(ui.draggable);

var p2 = ui.draggable.parent().offset();

ui.draggable.css({
top: parseInt(ui.draggable.css('top')) + (p1.top - p2.top),
left: parseInt(ui.draggable.css('left')) + (p1.left - p2.left)
});
}
}
});
});
    .bucket {
width: 400px;
height: 150px;
background: #ddd;
position: relative;
}

.draggable {
width: 50px;
height: 30px;
margin-top: 5px;
background: red;
position: absolute;
z-index: 10;
}

#destination {
background: #aaa;
position: relative;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://code.jquery.com/ui/1.12.0/jquery-ui.min.js"></script>
<div class="bucket" id="origin">
<div class="draggable" data-bucket="origin">Drop 1</div>
<div class="draggable" data-bucket="origin">Drop 2</div>
<div class="draggable" data-bucket="origin">Drop 3</div>
<div class="draggable" data-bucket="origin">Drop 4</div>
</div>
<div class="bucket" id="destination">
</div>

<pre id="status"></pre>

关于javascript - 将多个 div 拖入另一个 jQuery,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53482438/

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