javascript - jest.mock() 等同于 sinon.stub()

Question

在 Firebase SDK for Cloud Functions Quickstart 的所有示例测试中，都使用了 Mocha/Chai 和 Sinon...试图改用 Jest，我想知道 sinon.stub() 的正确等价物是什么？

我尝试了以下(仅用于测试 jest.mock() 验收...

const sinon = require('sinon');

const jest = require('jest');

describe('Cloud Functions', () => {

    before(() => {
      let myFunctions, adminInitStub;
      let adminInitMock;

      adminInitStub = sinon.stub(admin, 'initializeApp');
      adminInitMock = jest.mock(admin, 'initializeApp');

      myFunctions = require('../index');
      myFunctions = require('../index');

但是我得到一个错误:

1 失败

1) 云功能 “首先”钩子(Hook): TypeError: jest.mock 不是函数

我哪里错了......但我无法理解感谢反馈

Answer 1

已解决...

从mocking-es-and-commonjs-modules-with-jest-mock上明白了

However, when using export with require we would see an error such as:

TypeError: ourCode is not a function

The CommonJS module does not understand the ES Module it is trying to require. This is easily fixed, by adding a .functionNameBeingExported to the require, which for a default export is default.

externalModule.js
const ourCode = () => 'result';
export default ourCode;

testSubject.js
const ourCode = require('./externalModule').default;
// use ourCode()