android - 样式自定义弹出菜单

Question

我有一个图像按钮，按下时会显示一个弹出菜单。

public void showMenu (View v){
    PopupMenu popup = new PopupMenu(getBaseContext(), v);
    popup.getMenuInflater().inflate(R.menu.menu_launch_page, popup.getMenu());
    popup.show();

}

生成的菜单有深色背景。我如何设置弹出窗口的样式，以便更改背景颜色以及选择项目时的颜色。我正在使用 android:Theme.Holo.Light.NoActionBar，所以任何地方都没有涉及 Actionbar。

Answer 1

好的，你可以在这里试试，你也可以设置你的自定义适配器

您的 ButtonViewObject 是您单击以显示此弹出窗口的按钮

ListPopupWindow listPopupWindow = new ListPopupWindow(
            ListPopupWindowAppActivity.this);

//here you can set your custom adapter aswell
        listPopupWindow.setAdapter(new ArrayAdapter(
            ListPopupWindowAppActivity.this,
            R.layout.list_item, passyourarrayhere));
        listPopupWindow.setAnchorView(yourButtonViewObject);
        listPopupWindow.setWidth(300);
        listPopupWindow.setHeight(400);

listPopupWindow.setModal(true);
        listPopupWindow.setOnItemClickListener(
            ListPopupWindowAppActivity.this);

//when you click on yourButtonViewObject show listPopupWindow like this
listPopupWindow.show();

//and in onItemClick overiden method do similar as you do in listview