php - 有什么办法可以优化这个mysql查询吗？

Question

这是查询。我最感兴趣的是是否有更好的方法来获取我使用 GROUP_CONCAT 的内容，或者这是获取这些数据的好方法。然后我将其分解，并将 ids/name 放入一个数组中，然后使用 for 循环将它们回显。

SELECT 
    mov_id, 
    mov_title, 
    GROUP_CONCAT(DISTINCT categories.cat_name) as all_genres, 
    GROUP_CONCAT(DISTINCT cat_id) as all_genres_ids,  
    GROUP_CONCAT(DISTINCT case when gen_dominant = 1 then gen_catid else 0 end) as dominant_genre_ids, 
    GROUP_CONCAT(DISTINCT actors.act_name) as all_actors, 
    GROUP_CONCAT(DISTINCT actors.act_id) as all_actor_ids, 
    mov_desc, 
    mov_added, 
    mov_thumb, 
    mov_hits, 
    mov_numvotes, 
    mov_totalvote, 
    mov_imdb, 
    mov_release, 
    mov_html, 
    mov_type,
    mov_buytickets,
    ep_summary,
    ep_airdate,
    ep_id,
    ep_hits,
    ep_totalNs,
    ep_totalRs,
    mov_rating,
    mov_rating_reason,
    mrate_name,
    dir_id, 
    dir_name
FROM movies
LEFT JOIN _genres
    ON movies.mov_id = _genres.gen_movieid
LEFT JOIN categories
    ON _genres.gen_catid = categories.cat_id
LEFT JOIN _actors
    ON (movies.mov_id = _actors.ac_movid)
LEFT JOIN actors
    ON (_actors.ac_actorid = actors.act_id AND act_famous = 1)
LEFT JOIN directors
    ON movies.mov_director = directors.dir_id
LEFT JOIN movie_ratings
    ON movies.mov_rating = movie_ratings.mrate_id
LEFT JOIN episodes
    ON mov_id = ep_showid AND ep_season = 0 AND ep_num = 0
WHERE mov_id = *MOVIE_ID* AND mov_status = 1 
GROUP BY mov_id

查询的解释在这里

alt text http://www.krayvee.com/o2/explain.gif

Answer 1

就我个人而言，我会尝试将查询分解为多个查询。大多数情况下，我建议删除 Actor 和 Genre Joins，以便您可以摆脱所有这些 group_concat 函数。然后执行单独的查询来提取这些数据。不确定它是否会加快速度，但可能值得一试。