javascript - Facebook API Javascript JSON 响应

Question

function getUser()
{
    FB.api('/me', function(response) {
       console.log('Response is '+response);
       alert('Your name is ' + response.first_name);
       alert('Your last name is ' + response.last_name);
       alert('Your Gender is ' + response.gender);
       alert('Your status is '+response.username);
    }

我怎样才能打印出像下面这样的完整响应？

{
  "id": "blah blah", 
  "name": "blah blah", 
  "first_name": "blah blah", 
  "last_name": "blah blah", 
  "link": "https://www.facebook.com/blah blah", 
  "username": "blah blah", 
  "hometown": {
    "id": "106442706060302", 
    "name": "Pune, Maharashtra"
  }, 
  "location": {
    "id": "106377336067638", 
    "name": "Bangalore, India"
  }, 
  "bio": "╔══╗♫ ♪♫\n║██║\n║¨o•♫\n╚═|̲̅̅●̲̅̅|̅lιlllι ♫ I LoVe MuZiK!!\n\n█║▌│█│║▌║│█║▌│║\n® Copyright © 2012 ™\n█║▌│█│║▌║│█║▌│║\n\nReVoLt", 
  "gender": "male", 
  "relationship_status": "Single", 
  "timezone": 5.5, 
  "locale": "en_GB", 
  "verified": true, 
  "updated_time": "2012-06-15T05:33:31+0000", 
  "type": "user"
}

同样通过 respose.name 获取用户名。我如何获取参数位置中的位置，因为它是一个 JSON 数组？

Answer 1

使用 JSON.stringify(响应);它应该打印整个对象。

使用 JSON.parse() 或 jQuery.parseJSON();解析并获取响应对象的任何属性这里的例子:jsfiddle.net/epinapala/HrfkL 和这里:jsfiddle.net/epinapala/zfWWv/3

    var obj2 = JSON.parse('{"id":"579156356","name":"Vishal Jethani","first_name":"Vishal","last_name":"Jethani","link":"https://www.facebook.com/vishal.jethani","username":"vishal.jethani","hometown":{"id":"106442706060302","name":"Pune, Maharashtra"},"location":{"id":"106377336067638","name":"Bangalore, India"},"bio":"bye bye to bad characters","gender":"male","relationship_status":"Single","timezone":5.5,"locale":"en_GB","verified":true,"updated_time":"2012-06-15T05:33:31+0000","type":"user"}');
alert("Parsing with Json : " + obj2.location.name);​

对于请求者要求的多维数组:这应该有效:http://jsfiddle.net/epinapala/WQcDg/

var obj2 = JSON.parse('{"work":[{"employer":{"id":"185998961446429","name":"Pvt Ltd"}}]}');

alert("Parsing with Json : " + JSON.stringify(obj2.work[0].employer.name));