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php - 无法使用 PHP 插入 MySQL 表

转载 作者:行者123 更新时间:2023-11-29 15:00:09 24 4
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将新记录插入表中时遇到问题。有人愿意帮忙吗?

<?php include('config.php'); ?>
<?php

if(!empty($_POST['forename']) && !empty($_POST['surname']) && !empty($_POST['email']) && !empty($_POST['emailconfirm']) && !empty($_POST['password'])) {
if($_POST['email'] == $_POST['emailconfirm']) {
$forename = mysql_real_escape_string($_POST['forename']);
$surname = mysql_real_escape_string($_POST['surname']);
$email = mysql_real_escape_string($_POST['email']);
$password = md5(mysql_real_escape_string($_POST['password']));
register();
}
else { $errormessage = "Emails do not match"; }
}
else { $errormessage = "Not all fields filled"; }

function register() {
$check = mysql_query("SELECT * FROM Users WHERE EmailAddress = '".$email."'");
if (mysql_num_rows($check) == 1) {
$errormessage = "Account already exists with the email address provided";
}
else {
$register = mysql_query("INSERT INTO Users (EmailAddress, Password, Forename, Surname) VALUES('".$email."', '".$password."', '".$forename."', '".$surname."')");
$errormessage = "Account Added";
}
}
?>

我认为问题出在 MySQL 查询语句中?

最佳答案

register 函数中的变量超出了范围。需要将它们全局化。

function register() {
global $email, $password, $forename, $surname, $errormessage;

$check = mysql_query("SELECT * FROM Users WHERE EmailAddress = '".$email."'");
if (mysql_num_rows($check) == 1) {
$errormessage = "Account already exists with the email address provided";
}
else {
$register = mysql_query("INSERT INTO Users (EmailAddress, Password, Forename, Surname) VALUES('".$email."', '".$password."', '".$forename."', '".$surname."')");
$errormessage = "Account Added";
}
}

关于php - 无法使用 PHP 插入 MySQL 表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3432834/

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