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php - 如何从 PHP 脚本生成表格格式的输出

转载 作者:行者123 更新时间:2023-11-29 14:57:12 24 4
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以下是包含列和值的示例:

+----------------------------------------------------------------+| rate | conn/s | req/s | replies/s avg | errors | net io (KB/s) |+----------------------------------------------------------------+|  100 | 99.9   | 99.9  | 99.7          | 0      | 45.4          ||  120 | 119.7  | 119.7 | 120.0         | 0      | 54.4          ||  140 | 139.3  | 139.3 | 138.0         | 0      | 63.6          ||> 160 | 151.9  | 151.9 | 147.0         | 0      | 69.3          ||  180 | 132.2  | 129.8 | 137.4         | 27     | 59.6          ||  200 | 119.8  | 117.6 | 139.9         | 31     | 53.9          |+----------------------------------------------------------------+

最佳答案

假设你想在浏览器中显示并从MySQL中获取数据。使用此代码,将您的 dbnametablename 替换为正确的值:

<html>
<head><title>Result as Table</title></head>
<body>
<?php
$db_host = 'localhost';
$db_user = 'root';
$db_pwd = '';

$database = 'dbname';
$table = 'tablename';

if (!mysql_connect($db_host, $db_user, $db_pwd))
die("Can't connect to database");

if (!mysql_select_db($database))
die("Can't select database");

// sending query
$result = mysql_query("SELECT * FROM {$table}");
if (!$result) {
die("Query to show fields from table failed");
}

$fields_num = mysql_num_fields($result);

echo "<h1>Table: {$table}</h1>";
echo "<table border='1'><tr>";
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<td>{$field->name}</td>";
}
echo "</tr>\n";
// printing table rows
while($row = mysql_fetch_row($result))
{
echo "<tr>";

// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
echo "<td>$cell</td>";

echo "</tr>\n";
}
mysql_free_result($result);
?>
</body></html>

关于php - 如何从 PHP 脚本生成表格格式的输出,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4295477/

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