php - PHP 和 MySQL 中嵌套数组的输出/结构出现问题

Question

我正在尝试制作一个整洁、结构化的列表，在本例中是电影和放映日期。

$shows = array(
    array(
        "Thursday" => array(
            "17:00",
            "19:00")),
    array(
        "Friday" => array(
            "16:30",
            "18:45"
            "20:10")),
    array(
        "Saturday" => array(
            "18:30",
            "21:00"))
);

问题是我似乎无法以合理的方式打印出这些内容。在这种情况下，日子应该是动态的，而不是硬编码的。

for ($row = 0; $row < $shows.length(); $row++) //Haven't got a clue about the 'length()'
{
    print $shows[$row] . "<br>"; //Print the day.

    for (

   $col = 0; $col < $shows[$row].length(); $col++) //Loop through each day.
    {
        print (">" . $shows[$row][$col] . "<br>"); //Print each time of the day.
    }

}

我想做的是打印出每一天的相应时间。应该是这样的。

Thursday - 17:00
           19:00

Friday   - 16:30
           18:45
           20:10

Answer 1

foreach ($shows as $show) {
    foreach ($show as $day => $times) {
        echo $day;
        foreach ($times as $time) {
            echo $time;
        }
    }
}

但是，实际上，您应该像这样简化一下:

$shows = array(
    array('day' => 'Saturday', 'times' => array('17:00', '19:00')),
    …
);

foreach ($shows as $show) {
    echo $show['day'];
    foreach ($show['times'] as $time) {
        echo $time;
    }
}

或者，以计算机可解析的方式真正正确地做到这一点:

$shows = array(
    strtotime('2010-12-24 17:00:00'),
    strtotime('2010-12-24 19:00:00'),
    …
);

$lastDate = null;
foreach ($shows as $show) {
    if (!$lastDate || date('Y-m-d', $show) != date('Y-m-d', $lastDate)) {
        echo date('l', $show);
    }
    echo date('H:i', $show);
    $lastDate = $show;
}

:o)