javascript - 创建适用于智能感知的 javascript 函数

Question

我想利用 visual studio intellisense，因此我阅读了:

http://msdn.microsoft.com/en-us/library/bb514138.aspx

无论如何，为什么我没有得到 intellisense:

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

function Test() {
    /// <returns type="Customer"></returns>

    var c = new Object();
    $.ajax({
        async: false,
        dataType: "json",
        url: "Ajax/GetCustomer.aspx",
        success: function (foundCustomer) {
            // I know that found customer is of type Customer
            c = foundCustomer;
        }
    });

    return c;
}

var x = Test();
x. // No intellicense! why?

如何让 visual studio 知道该函数将返回类型为 Customer 的对象？例如，如果我将函数 Test 替换为: function Test(){ return new Customer(); } 然后智能将工作。

---

编辑

我最后的目标是:

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

Object.prototype.CastToCustomer = function(){
    /// <returns type="Customer"></returns>
    return this;
}

$.ajax({
    async: false,
    dataType: "json",
    url: "Ajax/GetCustomer.aspx",
    success: function (foundCustomer) {

        foundCustomer = foundCustomer.CastToCustomer();
        foundCustomer.// Intellicense does not work :(
    }
});

我得到了很多 json 对象，我想使用这个辅助函数来转换它们。

---

临时解决方案:

这就是我最终做的:

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

$.ajax({
    async: false,
    dataType: "json",
    url: "Ajax/GetCustomer.aspx",
    success: function (foundCustomer) {
        // this will never be true on real browser. It is always true in visual studio (visual studio will now think that found customer is of type Customer ;)
        if (document.URL.length == 0) foundCustomer = new Customer();

        foundCustomer.// Intellisense works!!!!
    }
});

Answer 1

您正在将返回值初始化为 Object所以这是 Intellisense 所基于的。如果将其初始化为空 Customer ，然后 Intellisense 将检测到它正在返回一个 Customer

function Test() {

    var c = new Customer(); //only for Intellisense

    $.ajax({...});

    return c;
}

Test(). //Customer members now appear

---

您还可以使用 /// <param />指定参数类型:

$.ajax({
    ...

        success: function (foundCustomer) {
           /// <param name='foundCustomer' type='Customer' />
           foundCustomer. //Customer members appear            
        }
});

---

最后，你的 document.URL.length技巧也可以用在类型转换方法中:

Object.prototype.CastToCustomer = function() {

  var c = new Customer();
  if (document.URL.length) c = this;
  return c;

}