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android - 如何使用 phonegap 在 Android 手机上显示摄像头

转载 作者:行者123 更新时间:2023-11-29 14:54:14 26 4
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我想在 Android 手机上使用 phonegap 捕捉图像。我尝试了 Phonegap 页面上发布的代码,但没有出现相机。感谢您的帮助。非常感谢。

这是我手机上的显示

It is the display on my phone, there is no camera

<!DOCTYPE html>
<html>
<head>
<title>Capture Photo</title>

<script type="text/javascript" charset="utf-8" src="cordova-1.6.0.js"></script>
<script type="text/javascript" charset="utf-8">

var pictureSource; // picture source
var destinationType; // sets the format of returned value

// Wait for Cordova to connect with the device
//
document.addEventListener("deviceready",onDeviceReady,false);

// Cordova is ready to be used!
//
function onDeviceReady() {
pictureSource=navigator.camera.PictureSourceType;
destinationType=navigator.camera.DestinationType;
}

// Called when a photo is successfully retrieved
//
function onPhotoDataSuccess(imageData) {
// Uncomment to view the base64 encoded image data
// console.log(imageData);

// Get image handle
//
var smallImage = document.getElementById('smallImage');

// Unhide image elements
//
smallImage.style.display = 'block';

// Show the captured photo
// The inline CSS rules are used to resize the image
//
smallImage.src = "data:image/jpeg;base64," + imageData;
}

// Called when a photo is successfully retrieved
//
function onPhotoURISuccess(imageURI) {
// Uncomment to view the image file URI
// console.log(imageURI);

// Get image handle
//
var largeImage = document.getElementById('largeImage');

// Unhide image elements
//
largeImage.style.display = 'block';

// Show the captured photo
// The inline CSS rules are used to resize the image
//
largeImage.src = imageURI;
}

// A button will call this function
//
function capturePhoto() {
// Take picture using device camera and retrieve image as base64-encoded string
navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50,
destinationType.DATA_URL });
}

// A button will call this function
//
function capturePhotoEdit() {
// Take picture using device camera, allow edit, and retrieve image as base64-encoded string
navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 20, allowEdit: true,
destinationType.DATA_URL });
}

// A button will call this function
//
function getPhoto(source) {
// Retrieve image file location from specified source
navigator.camera.getPicture(onPhotoURISuccess, onFail, { quality: 50,
destinationType: destinationType.FILE_URI,
sourceType: source });
}

// Called if something bad happens.
//
function onFail(message) {
alert('Failed because: ' + message);
}

</script>
</head>
<body>
<button onclick="capturePhoto();">Capture Photo</button> <br>
<button onclick="capturePhotoEdit();">Capture Editable Photo</button> <br>
<button onclick="getPhoto(pictureSource.PHOTOLIBRARY);">From Photo Library</button><br>
<button onclick="getPhoto(pictureSource.SAVEDPHOTOALBUM);">From Photo Album</button><br>
<img style="display:none;width:60px;height:60px;" id="smallImage" src="" />
<img style="display:none;" id="largeImage" src="" />
</body>
</html>

最佳答案

capturePhoto()capturePhotoEdit() 函数都需要更新 destinationType

navigator.camera.getPicture(
onPhotoDataSuccess,
onFail,
{
quality: 50,
destinationType.DATA_URL
}
);

应该是这样的,

navigator.camera.getPicture(
onPhotoDataSuccess,
onFail,
{
quality: 50,
destinationType: destinationType.DATA_URL
}
);

关于android - 如何使用 phonegap 在 Android 手机上显示摄像头,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10173892/

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