android 找到正确的电话号码

Question

给定一个字符串形式的电话号码，我如何找到存储在联系人中的正确值？

例子:
给出电话号码:9743343954
联系人中的电话号码:+919743343954

编辑:数字的长度不固定。

谢谢。

Answer 1

我不确定我是否理解您的意思，但也许这会对您有所帮助:

    //Find contact by given number
    Uri uri = Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI, Uri.encode("9743343954"));
    String[] projection = new String[] { PhoneLookup.NUMBER, PhoneLookup.NORMALIZED_NUMBER };
    Cursor c = getContentResolver().query(uri, projection, null, null, null);
    if (c.moveToFirst()) {// while(c.moveToNext()){
        //get number assigned by user to given contact, in this case 9743343954
        String number = c.getString(c.getColumnIndexOrThrow(PhoneLookup.NUMBER));
        //get normalized E164 number, in this case +919743343954
        String normalized = c.getString(c.getColumnIndexOrThrow(PhoneLookup.NORMALIZED_NUMBER));
        Toast.makeText(getApplicationContext(), "Number: " + number + "; normalized: " + normalized,
                Toast.LENGTH_LONG).show();
    }
    c.close();

要使此工作正常，请向项目 list 添加权限:

    <uses-permission android:name="android.permission.READ_CONTACTS" />