php - uksort 帮助 - 在单个需要帮助中使用 GROUP BY

Question

您好，我有一个在通过 uksort() 传递后看起来像这样的数组

    Array
(
    [3] => Array
        (
            [job_id] => 4
            [job_title] => Supercar Test Driver
            [company_name] => McLaren
            [logo_small] => small_mclaren001.png
            [logo_large] => large_mclaren002.png
            [employer_id] => 3
        )

    [2] => Array
        (
            [job_id] => 3
            [job_title] => Recruitment Consultant - Driving
            [company_name] => MoovJob.com
            [logo_small] => small_rac001.png
            [logo_large] => large_rac002.png
            [employer_id] => 2
        )

    [1] => Array
        (
            [job_id] => 5
            [job_title] => Postal Worker / Post Person
            [company_name] => Royal Mail
            [logo_small] => small_royalmail001.png
            [logo_large] => large_royalmail002.png
            [employer_id] => 4
        )

    [0] => Array
        (
            [job_id] => 6
            [job_title] => Another Job
            [company_name] => MoovJob.com
            [logo_small] => small_rac001.png
            [logo_large] => large_rac002.png
            [employer_id] => 2
        )

)

但是，如果在返回此数组的 SQL 中添加 GROUP BY company_name 数组中的最后一个条目消失，我想要实现的目标是将职位名称放在公司名称下，但只显示公司名称一次，与此类似的东西，

Company Name 1
Job Title 1 Job Title 2 Job Title 3

Company Name 2
Job Title 4

Company Name
Job Title 5 Job Title 6

我试图通过执行以下操作来实现这一目标，但我只能显示一个空缺，我做错了什么？

    <?php $oldemp   = "";?>
<?php foreach($jobs as $key => $value) : ?>
   <?php if ($oldemp != $value['company_name']) : ?>
        <?php $oldemp = $value['company_name']; ?>
        <section class="employer">
            <div class="job_holder">
                <img src="<?php echo base_url(); ?>media/uploads/users/<?php echo $value['logo_large']; ?>" width="198" height="148" alt="<?php echo $value['company_name']; ?>"/>
                <dl>
                    <dt><?php echo count($key); ?></dt>
                    <dd>Matches</dd>
                </dl>
    <?php endif;?>
            <span> + <a href="/jobwall/getjob/<?php echo $value['job_id']; ?>"><?php echo $value['job_title']; ?></a></span>
            </div>
        </section>
<?php endforeach; ?>


    function jobcmp($job1, $job2)
    {
        return strcmp($job1['company_name'], $job2['company_name']);
    }

Answer 1

尽管可以使用您的方法显示数据，但我通常发现以更方便的格式创建第二个数组要简单得多:

$groupedJobs = array();
foreach ($jobs as $data) {
    if (!isset($groupedJobs[$data['company_name']])) {
        $groupedJobs[$data['company_name']] = array();
    }
    $groupedJobs[$data['company_name']][] = $data;
}

这会创建一个新数组，使用公司名称作为键，并使用嵌套数组中该公司的职位作为值，为您提供如下所示的内容:

['MoovJob.com'] => Array
    (
        [0] => Array
            (
                (job data)
            ),
        [1] => Array 
            (
                (etc.)
            )
    ),
['McLaren'] = Array
    (
        (etc)
    )

这样循环遍历这个数组并显示就容易多了:

foreach ($groupedJobs as $companyName => $jobs) {
    echo $companyName;
    foreach ($jobs as $job) {
        echo $job['job_title'].'<br />';
    }
}