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javascript - 如何显示点击目标的源节点?

转载 作者:行者123 更新时间:2023-11-29 14:45:35 25 4
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如何使用 D3 在强制有向图中显示单击的目标节点的源节点名称?

下面的片段来自一些 example code for directed graphs by Mike Bostock .我怎样才能着手修改这个基本代码,以便当在图表上单击一个节点时,该节点的目标值显示在屏幕上(在这种情况下,我想显示 name 属性) ?

例如 "nodes" 中的第 0 个元素是:

"nodes":[
{"name":"Myriel","group":1},
...
]

"links" 中,目标定义如下:

"links":[
{"source":1,"target":0,"value":1}, // Napoleon
{"source":2,"target":0,"value":8}, // Mlle.Baptistine
{"source":3,"target":0,"value":10}, // Mme.Magloire
{"source":3,"target":2,"value":6},
{"source":4,"target":0,"value":1}, // CountessdeLo
{"source":5,"target":0,"value":1}, // Geborand
{"source":6,"target":0,"value":1}, // Champtercier
{"source":7,"target":0,"value":1}, // Cravatte
{"source":8,"target":0,"value":2}, // Count
{"source":9,"target":0,"value":1}, // OldMan
...
{"source":11,"target":0,"value":5}, // Valjean
...
]

然后点击节点 Myriel 会显示:

Napoleon,Mlle.Baptistine,Mme.Magloire,CountessdeLo,Geborand,Champtercier,Cravatte,Count,OldMan,Valjean

Myriel 位于图中的此处:

enter image description here

下面是 JavaScript 代码:

var width = 960,
height = 500;
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var color = d3.scale.category20();
var force = d3.layout.force()
.charge(-120)
.linkDistance(30)
.size([width, height]);
d3.json("https://gist.githubusercontent.com/mbostock/4062045/raw/9653f99dbf6050b0f28ceafbba659ac5e1e66fbd/miserables.json", function(error, graph) {
if (error) throw error;
force
.nodes(graph.nodes)
.links(graph.links)
.start();
var link = svg.selectAll(".link")
.data(graph.links)
.enter().append("line")
.attr("class", "link")
.style("stroke-width", function(d) { return Math.sqrt(d.value); });
var node = svg.selectAll(".node")
.data(graph.nodes)
.enter().append("circle")
.attr("class", "node")
.attr("r", 5)
.style("fill", function(d) { return color(d.group); })
.call(force.drag)
.on("click",function(d){
var targets = graph.links.filter(function(i){
return i.target.name == d.name
});
tip.show( targets.map(function(i){ return i.source.name;}) );

});
node.append("title")
.text(function(d) { return d.name; });
force.on("tick", function() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node.attr("cx", function(d) { return d.x; })
.attr("cy", function(d) { return d.y; });
});
});

var width = 960,
height = 500;
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var color = d3.scale.category20();
var force = d3.layout.force()
.charge(-120)
.linkDistance(30)
.size([width, height]);
d3.json("https://gist.githubusercontent.com/mbostock/4062045/raw/9653f99dbf6050b0f28ceafbba659ac5e1e66fbd/miserables.json", function(error, graph) {
if (error) throw error;
force
.nodes(graph.nodes)
.links(graph.links)
.start();
var link = svg.selectAll(".link")
.data(graph.links)
.enter().append("line")
.attr("class", "link")
.style("stroke-width", function(d) { return Math.sqrt(d.value); });
var node = svg.selectAll(".node")
.data(graph.nodes)
.enter().append("circle")
.attr("class", "node")
.attr("r", 5)
.style("fill", function(d) { return color(d.group); })
.call(force.drag)
.on("click",function(d){
var targets = graph.links.filter(function(i){
return i.target.name == d.name
});
tip.show( targets.map(function(i){ return i.source.name;}) );

});
node.append("title")
.text(function(d) { return d.name; });
force.on("tick", function() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node.attr("cx", function(d) { return d.x; })
.attr("cy", function(d) { return d.y; });
});
});
.node {
stroke: #fff;
stroke-width: 1.5px;
}
.link {
stroke: #999;
stroke-opacity: .6;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.0/d3.min.js"></script>

最佳答案

在每个节点上添加一个点击事件,然后在里面我们可以得到所有的targets通过过滤 graph.links数组,这样我们只有 target.name 的元素与点击的节点名称相同 d.name .一旦我们有了,您就可以使用 .map()返回带有 .source.name 的数组给name里面的那些元素 targets :

  .on("click",function(d) { 
var targets = graph.links.filter(function(i){
return i.target.name==d.name;
});
tip.show( targets.map(function(i){ return i.source.name; }) );
});

var tip = d3.tip().attr('class', 'd3-tip').html(function(d) { return d; });

var width = 960,
height = 500;
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);

svg.call(tip);

var color = d3.scale.category20();
var force = d3.layout.force()
.charge(-120)
.linkDistance(30)
.size([width, height]);
d3.json("https://gist.githubusercontent.com/mbostock/4062045/raw/9653f99dbf6050b0f28ceafbba659ac5e1e66fbd/miserables.json", function(error, graph) {
if (error) throw error;
force
.nodes(graph.nodes)
.links(graph.links)
.start();
var link = svg.selectAll(".link")
.data(graph.links)
.enter().append("line")
.attr("class", "link")
.style("stroke-width", function(d) { return Math.sqrt(d.value); });
var node = svg.selectAll(".node")
.data(graph.nodes)
.enter().append("circle")
.attr("class", "node")
.attr("r", 5)
.style("fill", function(d) { return color(d.group); })
.call(force.drag)
.on("click",function(d){
var targets = graph.links.filter(function(i){
return i.target.name == d.name
});
tip.show( targets.map(function(i){ return i.source.name;}) );

});
node.append("title")
.text(function(d) { return d.name; });
force.on("tick", function() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node.attr("cx", function(d) { return d.x; })
.attr("cy", function(d) { return d.y; });
});
});
.node {
stroke: #fff;
stroke-width: 1.5px;
}
.link {
stroke: #999;
stroke-opacity: .6;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.0/d3.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3-tip/0.6.7/d3-tip.min.js"></script>

现在为了轻松显示这些值 d3-tip可以使用库。这将像这样为图表初始化:

var tip = d3.tip().attr('class', 'd3-tip').html(function(d) { return d; });
...
var svg = ..
svg.call(tip);

最后是 tip.show(...)第一个代码片段中的函数将在图表上显示这些项目。

关于javascript - 如何显示点击目标的源节点?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33362740/

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