javascript - lodash 合并和组合对象

Question

我有一个对象数组，如下所示，我使用 sequelize ORM 从我的数据库中读取这些对象:我想要一个部分的所有视频，但使用 sequelize 返回的效果更好:

[{
    "id": 2,
    "name": "Ru",
    "subsection": 1,
    "Video": {
      "id": 11,
      "source": "sourrrccrsss22222",
      "videoSubSection": 2
    }
  },
  {
    "id": 2,
    "name": "Ru",
    "subsection": 1,
    "Video": {
      "id": 12,
      "source": "sourrrccrsss111",
      "videoSubSection": 2
    }
  },
  {
    "id": 1,
    "name": "Oc",
    "subsection": 1,
    "Video": {
      "id": 13,
      "source": "sourrrcc",
      "videoSubSection": 1
    }
  },
  {
    "id": 1,
    "name": "Oc",
    "subsection": 1,
    "Video": {
      "id": 14,
      "source": "sourrrcc",
      "videoSubSection": 1
    }
  }]

有没有办法合并和组合我的数组中的对象以获得类似这样的东西:

[{
    "id": 2,
    "name": "Ru",
    "subsection": 1,
    "Video": [{
      "id": 11,
      "source": "sourrrccrsss22222",
      "videoSubSection": 2
    },{
      "id": 12,
      "source": "sourrrccrsss111",
      "videoSubSection": 2
    }]
  },
  {
    "id": 1,
    "name": "Oc",
    "subsection": 1,
    "Video": [{
      "id": 13,
      "source": "sourrrcc",
      "videoSubSection": 1
    },{
      "id": 14,
      "source": "sourrrcc",
      "videoSubSection": 1
    }]
  }

最接近的函数是 _.mergeWith(object, sources, customizer) 但我遇到的主要问题是我有一个对象并且需要合并这个对象。

Answer 1

在纯 Javascript 中，您可以使用 Array#forEach()使用数组的临时对象。

var data = [{ id: 2, name: "Ru", subsection: 1, Video: { id: 11, source: "sourrrccrsss22222", VideoSubSection: 2 } }, { id: 2, name: "Ru", subsection: 1, Video: { id: 12, source: "sourrrccrsss111", VideoSubSection: 2 } }, { id: 1, name: "Oc", subsection: 1, Video: { id: 13, source: "sourrrcc", VideoSubSection: 1 } }, { id: 1, name: "Oc", subsection: 1, Video: { id: 14, source: "sourrrcc", VideoSubSection: 1 } }],
    merged = function (data) {
        var r = [], o = {};
        data.forEach(function (a) {
            if (!(a.id in o)) {
                o[a.id] = [];
                r.push({ id: a.id, name: a.name, subsection: a.subsection, Video: o[a.id] });
            }
            o[a.id].push(a.Video);
        });
        return r;
    }(data);

document.write('<pre>' + JSON.stringify(merged, 0, 4) + '</pre>');