Javascripting 没有按预期工作，并且没有返回语法错误？

Question

好的，我正在尝试使用 JavaScript 来验证表单，然后在使用正确的信息验证所有表单后显示“谢谢”消息。我可以使用它来验证名字、电子邮件地址和 radio 选择，但是我似乎无法使用它来验证状态选择或显示感谢消息，但我也使用了我的浏览器(Firefox) 用于挖掘语法错误的开发控制台。没有显示。有帮助吗？

一小段代码在下面，一个指向整个代码的 jsfiddle 链接，下面是 HTML。

function validForm() { // reference point 
/* first name, email, comments and phone */
var fname = document.form1.fname;
var email = document.form1.email;
var comments = document.form1.comments;
var phone1 = document.form1.phone1;
var phone2 = document.form1.phone2;
var phone3 = document.form1.phone3;
/* collecting the error spans for later use */
var fnErr = document.getElementById('fnErr');
var lnErr = document.getElementById('lnErr');
var emErr = document.getElementById('emErr');
var phErr = document.getElementById('phErr');
var cmErr = document.getElementById('cmErr');
var state = document.getElementById('stErr');
    if(fname.value=="") {
    fnErr.innerHTML = "We need your name, please.";
    fname.focus();
    return false;
} else {
    fnErr.innerHTML = "";
}
    if(email.value=="") {
    emErr.innerHTML = "We need your email, please.";
    email.focus();
    return false;
} else {
    emErr.innerHTML = "";
}
if(state.value=="none") {
    fnErr.innerHTML = "Please select your state.";
    state.focus();
    return false;
} else {
    fnErr.innerHTML = "";
}
/[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}/i;
    if(isNaN(phone1.value) || isNaN(phone2.value) ||
isNaN(phone3.value)) {
    phErr.innerHTML = "If you include a phone number it should be numbers only.";
    phone1.select();
    return false;
} else {
    phErr.innerHTML = ""; 
}
var notices = document.form1.notices;
var selected;
for(var i=0;i<notices.length;i++) {
    if(notices[i].checked) {
    selected = notices[i].value;  
    }
}
/* set up a message for a advert recipient */
var msg = "Thank you, <b>"+fname.value
+"!</b> Your message has been received and one of our representatives will reply to <a href='"
+email.value+"'>"+email.value+"</a> within a day or two. Relax, and enjoy the rest of the site!";
if(selected != undefined) {
    document.getElementById('notePref').innerHTML = "";
    if (selected == "yes") {  // here's where we test the contents of "selected"
        document.getElementById('fnlMsg').innerHTML = msg;
    } else {
        document.getElementById('fnlMsg').innerHTML = "<strong>"+fname.value+"</strong>, thank you for your feedback!";
    }
     var contactForm = document.getElementById('registerForm').setAttribute('class','hide');
     var loseSep = document.getElementsByClassName('spec');
     loseSep[0].setAttribute('class', 'hide');
} else {
    document.getElementById('notePref').innerHTML = "Please make a selection:";
}
} // reference point

https://jsfiddle.net/xp5e099y/2/

Answer 1

首先:您没有 id 为 ="fnlMsg"的位置(div/span/等)

第二:你没有 id 为 ="contactForm"的地方(div/span/etc)

然后改变你的html

<select name="state">

与

<select id="state">

和你的脚本

var state = document.getElementById('stErr');

到

var state = document.getElementById('state');