gpt4 book ai didi

php - PHP 分页类和 AJAX/JQuery 的链接错误

转载 作者:行者123 更新时间:2023-11-29 14:36:26 25 4
gpt4 key购买 nike

在我的搜索结果页面上,用户可以使用左侧的按钮修改他的搜索结果。这些按钮使用 jquery 更新 div 中的结果。但是,当使用 jquery 重新调用结果并回显到 div 时,下一页、最后一页等的链接无法正常工作。这是我正在使用的分页类:

  class pagination
{
var $page = 1; // Current Page
var $perPage = 10; // Items on each page, defaulted to 10
var $showFirstAndLast = false; // if you would like the first and last page options.

function generate($array, $perPage = 10)
{
// Assign the items per page variable
if (!empty($perPage))
$this->perPage = $perPage;

// Assign the page variable
if (!empty($_GET['page'])) {
$this->page = $_GET['page']; // using the get method
} else {
$this->page = 1; // if we don't have a page number then assume we are on the first page
}

// Take the length of the array
$this->length = count($array);

// Get the number of pages
$this->pages = ceil($this->length / $this->perPage);

// Calculate the starting point
$this->start = ceil(($this->page - 1) * $this->perPage);

// Return the part of the array we have requested
return array_slice($array, $this->start, $this->perPage);
}

function links()
{
// Initiate the links array
$plinks = array();
$links = array();
$slinks = array();

// Concatenate the get variables to add to the page numbering string
if (count($_GET)) {
$queryURL = '';
foreach ($_GET as $key => $value) {
if ($key != 'page') {
$queryURL .= '&'.$key.'='.$value;
}
}
}

// If we have more then one pages
if (($this->pages) > 1)
{
// Assign the 'previous page' link into the array if we are not on the first page
if ($this->page != 1) {
if ($this->showFirstAndLast) {
$plinks[] = ' <a href="?page=1'.$queryURL.'">&laquo;&laquo; First </a> ';
}
$plinks[] = ' <a href="?page='.($this->page - 1).$queryURL.'">&laquo; Prev</a> ';
}

// Assign all the page numbers & links to the array
for ($j = 1; $j < ($this->pages + 1); $j++) {
if ($this->page == $j) {
$links[] = ' <a class="selected">'.$j.'</a> '; // If we are on the same page as the current item
} else {
$links[] = ' <a href="?page='.$j.$queryURL.'">'.$j.'</a> '; // add the link to the array
}
}

// Assign the 'next page' if we are not on the last page
if ($this->page < $this->pages) {
$slinks[] = ' <a href="?page='.($this->page + 1).$queryURL.'"> Next &raquo; </a> ';
if ($this->showFirstAndLast) {
$slinks[] = ' <a href="?page='.($this->pages).$queryURL.'"> Last &raquo;&raquo; </a> ';
}
}

// Push the array into a string using any some glue
return implode(' ', $plinks).implode($this->implodeBy, $links).implode(' ', $slinks);
}
return;
}
}
?>

如果结果显示在search.php上,并且从search_again.php调用jqueried修改结果,则分页链接(NEXT、LAST等)将跟随search.php,并且不会使用search_again.php更新。

我尝试改变这个:

$slinks[] = ' <a href="?page='.($this->page + 1).$queryURL.'"> Next &raquo; </a> ';

对此:

$slinks[] = ' <a href="'.$_SERVER['PHP_SELF'].'?page='.($this->page + 1).$queryURL.'"> Next &raquo; </a> ';

它确实有点作用,但是单击此链接时,它将被加载到整个页面本身,而不是局限于 search.php 上的结果 div。有人对这个有经验么?谢谢

编辑:这是我的 JQuery:

$(document).ready(function(){
$("#button").click(function(){
var miles = $('#miles').val();
$.ajax({
url: 'thetestsession.php', //the variable miles is set being $_GET
data: 'miles=' + miles, //on this page and set to session
type: 'GET', //variable. miles is variable
//that a user can modify his
//search with.
success: function(results) {
$("#results").html(results); //#results is the div
//alert("Ok.");
}
}); //then i load thetestresults.php
$("#results").load('thetestresults.php'); //this is the page where the re-query
return false; //takes place.
});
});

最佳答案

如果将 ID“#button”添加到 php.ini 中的链接标记,可能会起作用。我想你忘了...如果我错了请纠正我!问候

关于php - PHP 分页类和 AJAX/JQuery 的链接错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8935891/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com