android - 将 recyclerview 项目限制为仅 10 个而不使用过滤器分页

Question

我正在使用包含 283 个项目的 Recycler View 和一个普通的 TextView 来过滤列表。

我只想一直显示10条记录。

我不能使用 getCount(或 GetItemCount)，因为当我过滤列表时它会给我 IndexOutOfBoundsExceptions，还有其他方法可以做到这一点吗？

public class RealmAutoCompleteAdapter extends RecyclerView.Adapter<RealmAutoCompleteAdapter.ProductViewHolder>  {
Realm realm;

RealmChangeListener<RealmResults<FieldsItem>> realmChangeListener;
RealmResults<FieldsItem> items;
String searchTerm;

public RealmAutoCompleteAdapter(Realm realm, RealmResults<FieldsItem> items) {
    this.realm = realm;
    this.realmChangeListener = new RealmChangeListener<RealmResults<FieldsItem>>() {
        @Override
        public void onChange(RealmResults<FieldsItem> results) {
            notifyDataSetChanged();
        }
    };
    this.items = items;
    items.addChangeListener(realmChangeListener);
}

@Override
public ProductViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
    return new ProductViewHolder(LayoutInflater.from(parent.getContext()).inflate(R.layout.autocomplete_row, parent, false));
}

@Override
public void onBindViewHolder(ProductViewHolder holder, int position) {
    FieldsItem item = items.get(position);
    holder.title.setText(item.getTitle());
}

public void updateInput(String input) {
    this.searchTerm = input;
    if(items != null && items.isValid()) {
        items.removeAllChangeListeners();
    }
    RealmQuery<FieldsItem> query = realm.where(FieldsItem.class);
    if(searchTerm != null && !"".equals(searchTerm)) {
        query = query.contains("title", searchTerm, Case.INSENSITIVE);
    }
    items = query.findAll();
    items.addChangeListener(realmChangeListener);
    notifyDataSetChanged();
}

@Override
public int getItemCount() {
    if(items == null || !items.isValid()) {
        return 0;
    }
    return items.size();
}

static class ProductViewHolder extends RecyclerView.ViewHolder {

    TextViewWithFont title;
    ProductViewHolder(View itemView) {
        super(itemView);
        title = (TextViewWithFont)itemView.findViewById(R.id.title);
    }

}

Answer 1

你可以这样做:

return Math.min(items.size(), 10);