android - 如何删除 ksoap 中的命名空间声明？

Question

马上，这是我的 Soap 调用实现，减去不相关的位。

public class MySoapClient implements AbstractSoapClient
{

    private String NAMESPACE = "http://www.examples.com/wsdl/MyService/";
    private String METHOD_NAME = "getPersonDetails";
    private String SOAP_ACTION = "http://www.examples.com/getPersonDetails/";
    String URL = "http://192.168.0.10:8088/mockMyServiceBinding?WSDL";


    public Object process() throws Exception
    {
        SoapSerializationEnvelope envelope = generateEnvelope();
        return responseObject = makeCall(envelope);
    }

    private SoapSerializationEnvelope generateEnvelope()
    {
        // dont set a namespace for the requestobject, otherwise ksoap adds implicit namespaces onto request elements
        SoapObject requestObject = new SoapObject("", METHOD_NAME);
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet = true;
        envelope.implicitTypes = true;

        requestObject.addProperty("name", "Dave");
        envelope.setOutputSoapObject(requestObject);

        return envelope;
    }

    private Object makeCall(SoapSerializationEnvelope envelope)
    {
        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
        try
        {
            androidHttpTransport.debug = true;
            androidHttpTransport.call(SOAP_ACTION, envelope);
            return envelope.bodyIn;
        }
        catch (Exception e)
        {
            e.printStackTrace();
            return e;
        }
    }


}

我认为问题出在 SoapObject requestObject = new SoapObject("", METHOD_NAME); 部分。

如果我使用 SoapObject requestObject = new SoapObject("", METHOD_NAME); 然后我在 bodyOut 中得到这个:

<v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema"
            xmlns:c="http://schemas.xmlsoap.org/soap/encoding/" xmlns:v="http://schemas.xmlsoap.org/soap/envelope/">
    <v:Header/>
    <v:Body>
        <getPersonDetails xmlns="" id="o0" c:root="1">
            <name>Dave</name>
        </getPersonDetails>
    </v:Body>
</v:Envelope>

如果我使用 SoapObject requestObject = new SoapObject(NAMESPACE, METHOD_NAME); 然后我在 bodyOut 中得到这个:

<v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema"
            xmlns:c="http://schemas.xmlsoap.org/soap/encoding/" xmlns:v="http://schemas.xmlsoap.org/soap/envelope/">
    <v:Header/>
    <v:Body>
        <n0:getPersonDetails id="o0" c:root="1" xmlns:n0="http://www.examples.com/wsdl/MyService/">
            <name i:type="d:string">Dave</name>
        </n0:getPersonDetails>
    </v:Body>
</v:Envelope>

但是..SoapUI 只接受以下作为有效的 XML 请求:

<v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema"
            xmlns:c="http://schemas.xmlsoap.org/soap/encoding/" xmlns:v="http://schemas.xmlsoap.org/soap/envelope/">
    <v:Header/>
    <v:Body>
        <getPersonDetails>
            <name>Dave</name>
        </getPersonDetails>
    </v:Body>
</v:Envelope>

出于某种原因，它不喜欢 xmlns="http://www.examples.com/getPersonDetails/"id="o0"c:root="1" 部分，但我找不到删除它的方法，请帮忙!

那么我怎样才能完全删除 xmlns 声明呢？创建 SoapObject 并将命名空间设置为“”感觉很“脏”

Answer 1

一起玩

envelope.implicitTypes = true;

还有

envelope.setAddAdornments(false);

看看你是否让它做你想做的事。还要记住，最终请求是完全有效的，这将取决于您的服务器是否可以接受它而不是 SoapUI。