php - Mysql 连接并回显所有行，有条件

Question

我需要连接两个表，我已经有了第一个表的代码:

$query = "SELECT * FROM civicrm_event"; 

$result = mysql_query($query) or die(mysql_error());

while($row = mysql_fetch_array($result)){
$row = mysql_fetch_array($result) or die(mysql_error());
echo $row['title_en_US']. " - ". $row['id'];
echo "<br />";

我需要将其与另一个名为 civicrm_participant 的项目加入，我需要在其中提取 contact_id

选择该表的子句是:

civicrm_event.id = civicrm_participant.event_id

然后我需要回显[title_en_US] [id] [contact_id]帮助...

Answer 1

You should read joins in mysql

做这样的事情:

$query = "SELECT ce.title_en_US, ce.id, cp.event_id FROM civicrm_event AS ce JOIN civicrm_participant AS cp ON ce.id=cp.event_id";