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sql - 从 postgres jsonb 列中提取字段

转载 作者:行者123 更新时间:2023-11-29 14:26:48 25 4
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我有一个带有 jsonb 列的 postgres 表,其值如下:

 id  |  messageStatus       |   payload
-----|----------------------|-------------
1 | 123 | {"commissionEvents":[{"id":1,"name1":"12","name2":15,"name4":"apple","name5":"fruit"},{"id":2,"name1":"22","name2":15,"name4":"sf","name5":"fdfjkd"}]}
2 | 124 | {"commissionEvents":[{"id":3,"name1":"32","name2":15,"name4":"sf","name5":"fdfjkd"},{"id":4,"name1":"42","name2":15,"name4":"apple","name5":"fruit"}]}
3 | 125 | {"commissionEvents":[{"id":5,"name1":"42","name2":15,"name4":"apple","name5":"fdfjkd"},{"id":6,"name1":"52","name2":15,"name4":"sf","name5":"fdfjkd"},{"id":7,"name1":"62","name2":15,"name4":"apple","name5":"fdfjkd"}]}

这里的 payload 列是一个 jsonb 数据类型,我想编写一个 postgres 查询以从 name4 = apple 的 commissionEvents 中获取 name1。

所以我的结果会是这样的:

enter image description here

由于我是这个 jsonb 的新手,任何人都可以建议我一些解决方案。

最佳答案

您需要取消所有数组元素的嵌套,然后您可以对其应用 WHERE 条件以过滤掉具有所需名称的元素。

select t.id, x.o ->> 'name1'
from the_table t
cross join lateral jsonb_array_elements(t.payload -> 'commissionEvents') as x(o)
where x.o ->> 'name4' = 'apple'

在线示例:https://rextester.com/XWHG26387

关于sql - 从 postgres jsonb 列中提取字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56985673/

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