MySQL 与 WHERE 的 UNION

Question

我有以下2个表tableA a (id, 姓名, 项目, 日期)tableB b(id、aid、姓名、extracard)with tableA.id = tableB.aid(1对n关系)

Sample data for tableA:
| ID | NAME  | SURNAME | PROGRAM |   DATE    |  EXPIRES  |
----------------------------------------------------------
| 1  | TOM   | JONES   | 1,2,3   | 12/8/2012 | 12/8/2013 |
| 2  | JAMIE | OLIVER  | 4,5,6   | 15/8/2012 | 15/8/2013 |

Sample data for tableB:
| ID | AID | NAME  | SURNAME | CARD |
-------------------------------------
| 1  |  1  | ANNE  | JONES   |  1   |
| 2  |  1  | JACK  | BOWER   |  0   |
| 3  |  2  | KATE  | PERRY   |  1   |
| 4  |  2  | JOHN  | DOE     |  0   |
| 5  |  2  | HARRY | POTTER  |  0   |

在结果中，tableB 的每个成员都应具有 tableA 中的所有值(计划、日期、过期时间等...)，并且仅在同一列中显示 tableB 中的姓名、姓氏(合并？？)。另外，我需要在 (%id1 和 %id2) 之间使用 a.id 的 Between 子句，还需要使用 WHERE 语句来选择 tableB.card=1 的行

| a.ID | NAME  | SURNAME | PROGRAM |   DATE    |  EXPIRES  |
------------------------------------------------------------
|  1   | TOM   | JONES   | 1,2,3   | 12/8/2012 | 12/8/2013 |
|  1   | ANNE  | JONES   | 1,2,3   | 12/8/2012 | 12/8/2013 |
|  2   | JAMIE | OLIVER  | 4,5,6   | 15/8/2012 | 15/8/2013 |
|  2   | KATE  | PERRY   | 4,5,6   | 15/8/2012 | 15/8/2013 |

Answer 1

 SELECT * FROM 
   ( (SELECT a.id ,a.name,a.surname,a.program,a.date,a.expires 
    from tableA a left outer join tableB b 
    on b.aid=a.id 
    where b.card=1 and (a.id between '1' and '2'))
    UNION ALL
    (SELECT a.id ,b.name,b.surname,a.program,a.date,a.expires 
    from tableA a left outer join tableB b 
    on b.aid=a.id 
    where b.card=1 and (a.id between '1' and '2'))) t
    ORDER BY id

编辑:请引用http://sqlfiddle.com/#!2/d8227/1