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postgresql - 如何在 Postgresql 中获取 FK 引用的表

转载 作者:行者123 更新时间:2023-11-29 14:18:59 26 4
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对于给定的表,我试图获取所有列,包括它们的名称、类型、该列是主键还是外键,如果它是 FK,它指向哪个表。我在下面写了查询,但它似乎给了我引用列的内容,而不是相反:

select c.column_name, c.udt_name, constraint_type, kcu.table_name as references from information_schema.columns c
left outer join information_schema.constraint_column_usage u on c.column_name=u.column_name
left outer join information_schema.table_constraints t on u.constraint_name=t.constraint_name
left outer join information_schema.key_column_usage AS kcu on t.constraint_name = kcu.constraint_name
where c.table_name=@name

我不太担心边缘情况,我只是想反转引用列。感谢您的宝贵时间。

最佳答案

这是一个从给定表中获取所有外键及其指向的查询:

SELECT  c.conname,
t1.relname AS from_table,
a1.attname AS from_column,
t2.relname AS to_table,
a2.attname AS to_column
FROM pg_catalog.pg_constraint c,
pg_catalog.pg_class t1,
pg_catalog.pg_class t2,
pg_catalog.pg_attribute a1,
pg_catalog.pg_attribute a2,
pg_catalog.pg_namespace n1,
pg_catalog.pg_namespace n2
WHERE c.conrelid = t1.oid
AND c.confrelid = t2.oid
AND c.contype = 'f'
AND a1.attrelid = t1.oid
AND a1.attnum = ANY(c.conkey)
AND a2.attrelid = t2.oid
AND a2.attnum = ANY(c.confkey)
AND t1.relkind = 'r'
AND t2.relkind = 'r'
AND n1.oid = t1.relnamespace
AND n2.oid = t2.relnamespace
AND n1.nspname NOT IN ('pg_catalog', 'pg_toast')
AND n2.nspname NOT IN ('pg_catalog', 'pg_toast')
AND pg_catalog.pg_table_is_visible(t1.oid)
AND pg_catalog.pg_table_is_visible(t2.oid)
AND t1.relname = @name;

我看到您正在使用 information_schema 而不是 pg_catalog,所以最简单的方法可能是将我的查询转换为 CTE 或子查询,然后根据您的表名和列名。

编辑:听起来您只是需要一些帮助,将我的查询与您已有的查询结合起来。实际上,您的查询在如何进行连接方面存在很多错误,因此我重写了它以包含正确的外键结果:

SELECT  c.column_name,
c.udt_name,
t.constraint_type,
t.constraint_name,
x.to_table
FROM information_schema.columns c
LEFT OUTER JOIN (
SELECT t.constraint_type,
t.constraint_catalog,
t.constraint_schema,
t.constraint_name,
t.table_catalog,
t.table_schema,
t.table_name,
u.column_name
FROM information_schema.constraint_column_usage u
LEFT OUTER JOIN information_schema.table_constraints t
ON t.table_catalog = u.table_catalog
AND t.table_schema = u.table_schema
AND t.table_name = u.table_name
AND t.constraint_catalog = u.constraint_catalog
AND t.constraint_schema = u.constraint_schema
AND t.constraint_name = u.constraint_name
WHERE t.constraint_type IS DISTINCT FROM 'FOREIGN KEY'
) t
ON c.table_catalog = t.table_catalog
AND c.table_schema = t.table_schema
AND c.table_name = t.table_name
AND c.column_name = t.column_name
LEFT OUTER JOIN (
SELECT c.conname,
t1.relname AS from_table,
a1.attname AS from_column,
t2.relname AS to_table,
a2.attname AS to_column
FROM pg_catalog.pg_constraint c,
pg_catalog.pg_class t1,
pg_catalog.pg_class t2,
pg_catalog.pg_attribute a1,
pg_catalog.pg_attribute a2,
pg_catalog.pg_namespace n1,
pg_catalog.pg_namespace n2
WHERE c.conrelid = t1.oid
AND c.confrelid = t2.oid
AND c.contype = 'f'
AND a1.attrelid = t1.oid
AND a1.attnum = ANY(c.conkey)
AND a2.attrelid = t2.oid
AND a2.attnum = ANY(c.confkey)
AND t1.relkind = 'r'
AND t2.relkind = 'r'
AND n1.oid = t1.relnamespace
AND n2.oid = t2.relnamespace
AND n1.nspname NOT IN ('pg_catalog', 'pg_toast')
AND n2.nspname NOT IN ('pg_catalog', 'pg_toast')
AND pg_catalog.pg_table_is_visible(t1.oid)
AND pg_catalog.pg_table_is_visible(t2.oid)
) x
ON x.from_table = c.table_name
AND x.from_column = c.column_name
WHERE c.table_name = @cards
;

如果您有 NOT NULLCHECK 约束,此版本还可以防止出现大量重复行。

关于postgresql - 如何在 Postgresql 中获取 FK 引用的表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36652156/

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