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Php 到 MySql 选择查询不起作用

转载 作者:行者123 更新时间:2023-11-29 14:18:52 26 4
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我正在尝试获取一个 php 页面以从数据库中检索,我是 php 的新手,我已经用 google 搜索并阅读了,但我只是没有得到它。我有一个链接到 php 的 htm 页面,因为我试图根据所选的复选框和条件框中提交的信息返回一些数据。这是我到目前为止所拥有的,我一直在搞乱一些查询,试图让它工作,所以如果我能让其中一个工作,我就可以让剩下的去做我想做的事情。我知道我的代码可能不符合标准,但这不是我的职业,我只是一个试图让他的项目正常运行的学生。请引导我走向正确的方向。

编辑:这是我的一个学校项目,我必须使用他们服务器上的内容,在本例中恰好是 mysql。我没有得到任何返回,没有错误或任何东西。当我从 htm 页面转到 php 页面时,没有任何反应。我只是认为我可能必须从运行一个简单的查询开始只是为了调试以确保我可以获得任何内容,然后从那里进行修改。我以前从未使用过复选框,也从未运行过查询,所以我不得不相信这就是我的错误所在。我的所有插入和更新语句都在我的其他页面上工作,但代码用于选择语句并将它们放入变量的方式让我非常困惑。

我的htm页面:

   <html>
<head>
<meta http-equiv="Content-type" content="text/html;charset=UTF-8" />
<link href="style.css" rel="stylesheet" type="text/css" />
</head>
<body>
<span class="spanFormat"><form><input type="button" value="Create a New Ticket" onClick="window.location.href='listinput.htm'"></form></span>
<span class="spanFormat"><form><input type="button" value="Resolve a Ticket" onClick="window.location.href='resolution.htm'"></form></span>
<span class="spanFormat"><form><input type="button" value="Search for a Ticket" onClick="window.location.href='searchinput.htm'"></form></span>
<span class="spanFormat"><form><input type="button" value="View Documentation" onClick="window.location.href='documentation.htm'"></form></span>
<?php

DEFINE('DB_USER',);
DEFINE('DB_PASSWORD',);
DEFINE('DB_NAME',);
DEFINE('DB_HOST','localhost');

$con = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);

if(!$con){
die('Could not connect: '.mysql_error());
}
$db_selected = mysql_select_db(DB_NAME, $con);
if(!$db_selected){
die('can\'t use'. DB_NAME . ':'.mysql_error());
}
?>
<form action="searchinput.php" method="post">
<p>
How would you like to search?<br/>

<input type="checkbox" name="formDoor[]" id="Ticket_ID" value="Ticket_ID" />By Ticket Number<br />
<input type="checkbox" name="formDoor[]" id="Last_Name" value="Last_Name" />By Last Name<br />
<input type="checkbox" name="formDoor[]" id="Station_ID" value="Station_ID" />By Station ID<br />
<input type="checkbox" name="formDoor[]" id="Date" value="Date" />By Date<br />
<input type="checkbox" name="formDoor[]" id="Description" value="Description" />By Description
</p>

<td>Criteria</td>
<td><input type=text name="Criteria" size=30> </td>
</form>
<input type=submit name="submit" value="Search">
</body>
</html>

这是我的 php:

   <html>
<head>
<meta http-equiv="Content-type" content="text/html;charset=UTF-8" />
<link href="style.css" rel="stylesheet" type="text/css" />
</head>
<body>
<span class="spanFormat"><form><input type="button" value="Create a New Ticket" onClick="window.location.href='listinput.htm'"></form></span>
<span class="spanFormat"><form><input type="button" value="Resolve a Ticket" onClick="window.location.href='resolution.htm'"></form></span>
<span class="spanFormat"><form><input type="button" value="Search for a Ticket" onClick="window.location.href='searchinput.htm'"></form></span>
<span class="spanFormat"><form><input type="button" value="View Documentation" onClick="window.location.href='documentation.htm'"></form></span>
<?php

DEFINE('DB_USER',);
DEFINE('DB_PASSWORD',);
DEFINE('DB_NAME',);
DEFINE('DB_HOST','localhost');

$con = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);

if(!$con){
die('Could not connect: '.mysql_error());
}
$db_selected = mysql_select_db(DB_NAME, $con);
if(!$db_selected){
die('can\'t use'. DB_NAME . ':'.mysql_error());
}

extract($_POST);

$Ticket_ID = ($_POST['Criteria']);
$Last_Name = ($_POST['Criteria']);
$Station_ID = ($_POST['Criteria']);
$Date = ($_POST['Criteria']);
$Description = ($_POST['Criteria']);

if(isset($_POST['$Ticket_ID']))
{$sql = "select Ticket_ID, customer.Customer_ID, First_Name, Last_Name, Phone_Num, Email, stations.Station_ID, Room_ID, Floor_ID, building.Building_ID, Location, incident_sheet.Description, Summary, assign_groups.Group_ID, assign_groups.Description, resolutions.Resolution_ID, resolutions.Description from customer,stations,resolutions,assign_groups, building, incident_sheet WHERE customer.Customer_ID=incident_sheet.Customer_ID AND stations.Station_ID = customer.Station_ID AND building.Building_ID=stations.Building_ID AND resolutions.Resolution_ID = incident_sheet.Resolution_ID AND assign_groups.Group_ID = incident_sheet.Group_ID AND customer.Customer_ID = ($_POST[Criteria]);";

$result = mysql_query($sql, $con);

while($row = mysql_fetch_array($result))
{
$Ticket_ID = $row['Ticket_ID'];

echo
}
}
if(IsChecked('formDoor[]','Last_Name'))
{ $select_query = "select I.Ticket_ID, I.Customer_ID, I.Description, I.Date, C.Station_ID, C.First_Name, C.Last_Name, C.Phone_num, C.Email, S.Building_ID, S.Floor_ID, S.Room_ID, B.Location, A.Assign_Groups, R.Resolutions;
from incident_sheet I, customer C, stations S, building B, assign_groups A, resoultions R;
where I.Customer_ID = C.Customer_ID,
and C.Station_ID = S.Station_ID,
and S.Building_ID = B.Building_ID,
and I.Group_ID = A.Group_ID,
and I.Resoultion_ID = R.Resoultion_ID,
order by Last_Name;"
}
if(IsChecked('formDoor[]','Station_ID'))
{ $select_query = "select I.Ticket_ID, I.Customer_ID, I.Description, I.Date, C.Station_ID, C.First_Name, C.Last_Name, C.Phone_num, C.Email, S.Building_ID, S.Floor_ID, S.Room_ID, B.Location, A.Assign_Groups, R.Resolutions;
from incident_sheet I, customer C, stations S, building B, assign_groups A, resoultions R;
where I.Customer_ID = C.Customer_ID,
and C.Station_ID = S.Station_ID,
and S.Building_ID = B.Building_ID,
and I.Group_ID = A.Group_ID,
and I.Resoultion_ID = R.Resoultion_ID,
order by Station_ID;"
}
if(IsChecked('formDoor[]','Date'))
{ $select_query = "select I.Ticket_ID, I.Customer_ID, I.Description, I.Date, C.Station_ID, C.First_Name, C.Last_Name, C.Phone_num, C.Email, S.Building_ID, S.Floor_ID, S.Room_ID, B.Location, A.Assign_Groups, R.Resolutions;
from incident_sheet I, customer C, stations S, building B, assign_groups A, resoultions R;
where I.Customer_ID = C.Customer_ID,
and C.Station_ID = S.Station_ID,
and S.Building_ID = B.Building_ID,
and I.Group_ID = A.Group_ID,
and I.Resoultion_ID = R.Resoultion_ID,
order by Date;"
}
if(IsChecked('formDoor[]','Description'))
{ $select_query = "select I.Ticket_ID, I.Customer_ID, I.Description, I.Date, C.Station_ID, C.First_Name, C.Last_Name, C.Phone_num, C.Email, S.Building_ID, S.Floor_ID, S.Room_ID, B.Location, A.Assign_Groups, R.Resolutions;
from incident_sheet I, customer C, stations S, building B, assign_groups A, resoultions R;
where I.Customer_ID = C.Customer_ID,
and C.Station_ID = S.Station_ID,
and S.Building_ID = B.Building_ID,
and I.Group_ID = A.Group_ID,
and I.Resoultion_ID = R.Resoultion_ID,
order by Description;"
}
?>
<h3>This is the current ticket information: </h3>
<p>

<table>
<tr>
<td>First Name:</td>
<td><?php echo ("$First_Name"); ?></td>
</tr>
<tr>
<td>Last Name:</td>
<td><?php echo "$Last_Name"; ?></td>
</tr>
<tr>
<td>Email:</td>
<td><?php echo "$Email"; ?></td>
</tr>
<tr>
<td>Phone Number:</td>
<td><?php echo "$Phone_Num"; ?></td>
</tr>
<tr>
<td>Building:</td>
<td><?php echo "$Building_ID"; ?></td>
</tr>
<tr>
<td>Floor:</td>
<td><?php echo "$Floor_ID"; ?></td>
</tr>
<tr>
<td>Room:</td>
<td><?php echo "$Room_ID"; ?></td>
</tr>
<tr>
<td>Group:</td>
<td><?php echo "$Group_ID"; ?></td>
</tr>
<tr>
<td>Description:</td>
<td><?php echo "$Description"; ?></td>
</tr>

</table>

</p>
</body>
</html>

如果您能提供任何帮助使其正常工作,我们将不胜感激,感谢您花时间查看此内容。

最佳答案

你没有忘记定义这个值,对吧?不显示调试信息的服务器不会向您显示任何内容(可能是 500 错误页面)

DEFINE('DB_USER',<something>);
DEFINE('DB_PASSWORD',<something>);
DEFINE('DB_NAME',<something>);
DEFINE('DB_HOST','localhost');

关于Php 到 MySql 选择查询不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12113765/

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