android - 在不更改键顺序的情况下将 json 字符串转换为 json 对象

Question

我有一个如下所示的json字符串

{
"college": {
    "id": "RPD4007",
    "address": "#302, 1 st cross"
},
"deparment": {
    "department1": {
        "name": {
            "maths": {
                "chapter": 1,
                "name": "algebra",
                "module_id": "01"
            },
            "electronics": {
                "chapter": 1,
                "name": "ec",
                "module_id": "01"
            }
        }
    },
    "department2": {
        "name": {
            "english": {
                "chapter": 2,
                "name": "algebra",
                "module_id": "02"
            },
            "electrical": {
                "chapter": 2,
                "name": "algebra",
                "module_id": "02"
            }
        }
    }
}
}

我已经尝试将这个 json sring 转换为 json 对象，

string json_string = EntityUtils.toString(response.getEntity());
jObj = new JSONObject(json_string);//json object
JSONObject object = jobj.getJSONObject("college");

但我得到的 jobj 输出是 json 字符串的相反顺序。如下所示，

{
"college": {
    "id": "RPD4007",
    "address": "#302, 1 st cross"
},
"deparment": {
    "department2": {
        "name": {
            "electrical": {
                "chapter": 2,
                "name": "algebra",
                "module_id": "02"
            },
            "english": {
                "chapter": 2,
                "name": "algebra",
                "module_id": "02"
            }
        }
    },
    "department1": {
        "name": {
            "electronics": {
                "chapter": 1,
                "name": "ec",
                "module_id": "01"
            },
            "maths": {
                "chapter": 1,
                "name": "algebra",
                "module_id": "01"
            }
        }
    }
}
}

如何按原来的顺序得到它？

Answer 1

我认为您制作了两次 jsonObject。做这样的事情你有包含 JSON 数据的字符串为你所做的做一个对象

string json_string = EntityUtils.toString(response.getEntity());
jObj = new JSONObject(json_string);//json object

然后使用

进行循环以获取该对象内部的对象

 String college = jobj.getString("college");