gpt4 book ai didi

sql - WHERE ... IN 条件和子查询中的多列

转载 作者:行者123 更新时间:2023-11-29 14:10:15 24 4
gpt4 key购买 nike

是否可以重写 SQL 查询

SELECT DISTINCT ON (uid)
uid,
female,
given,
photo,
place
FROM words_social
WHERE uid IN (SELECT player1 FROM games)
OR uid IN (SELECT player2 FROM games)
ORDER BY uid, stamp DESC

在子查询中获取第一列 player1,然后从同一个表中获取列 player2

我四处搜索,似乎应该在此处使用 JOIN 而不是 2 个子查询,但无法弄清楚具体方法。

只是为了提供更多上下文 - 下面是有问题的 2 个表

CREATE TABLE words_social (
sid varchar(255) NOT NULL,

social integer NOT NULL CHECK (0 <= social AND social <= 6),
female integer NOT NULL CHECK (female = 0 OR female = 1),
given varchar(255) NOT NULL CHECK (given ~ '\S'),
family varchar(255),
photo varchar(255) CHECK (photo ~* '^https?://...'),
place varchar(255),
stamp integer NOT NULL, /* Only the most recent stamp is used */

uid integer NOT NULL REFERENCES words_users ON DELETE CASCADE,
PRIMARY KEY(sid, social)
);

CREATE TABLE words_games (
gid SERIAL PRIMARY KEY,

created timestamptz NOT NULL,
finished timestamptz,

player1 integer REFERENCES words_users(uid) ON DELETE CASCADE NOT NULL,
player2 integer REFERENCES words_users(uid) ON DELETE CASCADE,

played1 timestamptz,
played2 timestamptz,

mid integer /* REFERENCES words_moves */,

score1 integer NOT NULL CHECK (score1 >= 0),
score2 integer NOT NULL CHECK (score2 >= 0),

hand1 varchar[7] NOT NULL,
hand2 varchar[7] NOT NULL,
pile varchar[116] NOT NULL,

letters varchar[15][15] NOT NULL,
values integer[15][15] NOT NULL,
bid integer NOT NULL REFERENCES words_boards ON DELETE CASCADE
);

和实际的 CTE 查询,效果很好,但我想优化它:

CREATE OR REPLACE FUNCTION words_get_games(in_uid integer)
RETURNS TABLE (
out_gid integer,
out_created integer,
out_finished integer,
out_player1 integer,
out_player2 integer,
out_played1 integer,
out_played2 integer,
out_score1 integer,
out_score2 integer,
out_hand1 text,
out_hand2 text,
out_letters varchar[15][15],
out_values integer[15][15],
out_bid integer,
out_last_tiles jsonb,
out_last_score integer,
out_female1 integer,
out_female2 integer,
out_given1 varchar,
out_given2 varchar,
out_photo1 varchar,
out_photo2 varchar,
out_place1 varchar,
out_place2 varchar
) AS
$func$
WITH games AS (
SELECT
g.gid,
EXTRACT(EPOCH FROM g.created)::int AS created,
EXTRACT(EPOCH FROM g.finished)::int AS finished,
g.player1,
g.player2, -- can be NULL
EXTRACT(EPOCH FROM g.played1)::int AS played1,
EXTRACT(EPOCH FROM g.played2)::int AS played2,
g.score1,
g.score2,
ARRAY_TO_STRING(g.hand1, '') AS hand1,
REGEXP_REPLACE(ARRAY_TO_STRING(g.hand2, ''), '.', '?', 'g') AS hand2,
g.letters,
g.values,
g.bid,
m.tiles AS last_tiles,
m.score AS last_score
FROM words_games g LEFT JOIN words_moves m USING(mid)
WHERE g.player1 = in_uid
AND (g.finished IS NULL OR g.finished > CURRENT_TIMESTAMP - INTERVAL '1 day')
UNION SELECT
g.gid,
EXTRACT(EPOCH FROM g.created)::int AS created,
EXTRACT(EPOCH FROM g.finished)::int AS finished,
g.player2 AS player1,
g.player1 AS player2, -- can not be NULL
EXTRACT(EPOCH FROM g.played2)::int AS played1,
EXTRACT(EPOCH FROM g.played1)::int AS played2,
g.score2 AS score1,
g.score1 AS score2,
ARRAY_TO_STRING(g.hand2, '') AS hand1,
REGEXP_REPLACE(ARRAY_TO_STRING(g.hand1, ''), '.', '?', 'g') AS hand2,
g.letters,
g.values,
g.bid,
m.tiles AS last_tiles,
m.score AS last_score
FROM words_games g LEFT JOIN words_moves m USING(mid)
WHERE g.player2 = in_uid
AND (g.finished IS NULL OR g.finished > CURRENT_TIMESTAMP - INTERVAL '1 day')
),
social AS (
SELECT DISTINCT ON (uid)
uid,
female,
given,
photo,
place
FROM words_social
WHERE uid IN (SELECT player1 FROM games) /* How to optimize? */
OR uid IN (SELECT player2 FROM games)
ORDER BY uid, stamp DESC
)
SELECT
g.gid,
g.created,
g.finished,
g.player1,
g.player2,
g.played1,
g.played2,
g.score1,
g.score2,
g.hand1,
g.hand2,
g.letters,
g.values,
g.bid,
g.last_tiles,
g.last_score,
s1.female,
s2.female,
s1.given,
s2.given,
s1.photo,
s2.photo,
s1.place,
s2.place
FROM games g
LEFT OUTER JOIN social s1 ON g.player1 = s1.uid
LEFT OUTER JOIN social s2 ON g.player2 = s2.uid;

$func$ LANGUAGE sql;

最佳答案

SELECT DISTINCT ON (uid)
uid,
female,
given,
photo,
place
FROM words_social ws
INNER JOIN games g ON ws.uid = g.player1 OR ws.uid = g.player2
ORDER BY ws.uid, stamp DESC

关于sql - WHERE ... IN 条件和子查询中的多列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40304011/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com