sql - 如何将此 T-SQL 代码转换为 PostgreSQL/plpgsql

Question

我需要将以下 tsql 函数代码转换为 plpgsql 函数，但我完全不知道如何操作:

BEGIN
    DECLARE @StartDate DATETIME
    DECLARE @ResultDate DATETIME

    SET @StartDate = CONVERT(DATETIME, 0)

    SET @ResultDate = 
    CASE @Type
        WHEN 0 THEN DATEADD(mi, FLOOR(DATEDIFF(mi, @StartDate, @Date) / CAST(@Interval AS FLOAT)) * @Interval, @StartDate)
        WHEN 1 THEN DATEADD(mi, CEILING(DATEDIFF(mi, @StartDate, @Date) / CAST(@Interval AS FLOAT)) * @Interval, @StartDate)
        ELSE @Date
END

RETURN @ResultDate

这里是全文:

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO

ALTER FUNCTION [dbo].[GetIntervalDate] 

(
    @Date DATETIME,
    @Type INT,
    @Interval INT
)  
RETURNS DATETIME

AS

BEGIN

DECLARE @StartDate DATETIME

DECLARE @ResultDate DATETIME

    SET @StartDate = CONVERT(DATETIME, 0)

    SET @ResultDate = 
    CASE @Type
        WHEN 0 THEN DATEADD(mi, FLOOR(DATEDIFF(mi, @StartDate, @Date) / CAST(@Interval AS FLOAT)) * @Interval, @StartDate)
        WHEN 1 THEN DATEADD(mi, CEILING(DATEDIFF(mi, @StartDate, @Date) / CAST(@Interval AS FLOAT)) * @Interval, @StartDate)
        ELSE @Date
    END

    RETURN @ResultDate
END

Answer 1

明白了:

CREATE FUNCTION get_interval_date("@Date" timestamp, "@Type" int, "@Interval" int)
    RETURNS timestamp with time zone AS
$BODY$
DECLARE
    _mystamp timestamp;
    _round_secs decimal;
BEGIN
    _round_secs := "@Interval"::decimal;

    IF "@Type" = 0 THEN
        RETURN timestamptz 'epoch'
             + FLOOR((EXTRACT(EPOCH FROM "@Date"))::int / _round_secs) * _round_secs * INTERVAL '1 second';
    ELSIF "@Type" = 1 THEN  
        RETURN timestamptz 'epoch'
             + CEIL((EXTRACT(EPOCH FROM "@Date"))::int / _round_secs) * _round_secs * INTERVAL '1 second';
    ELSE
        RETURN "@Date";
    END IF;
END;
$BODY$ LANGUAGE 'plpgsql' IMMUTABLE;

也许其他人需要这样的东西。