php - 多个管理员的 Codeigniter 角色

Question

大家好，我需要有关 codeigniter 角色或权限的帮助。我有一个用户角色(管理员):

数据库中的表用户:

id   int(11)    
email    varchar(100)   
password varchar(128)       
name     varchar(100)

在我的管理面板中，我有(page.php Controller )=页面管理，页面顺序，(agent.php Controller )=添加，编辑，删除...，(gyms)=添加，编辑，删除... ,(article.php Controller )

我有 21 个部分，对于每个部分我有不止一种处理，我想要的是为每个部分分配一个管理员，只能编辑和查看他的部分。所以我将有 21 个section_admin 和一个(或多个)global_admin 来管理一切

我在用户表中添加了一个名为 type 的其他字段:类型 varchar(50)它将有两个值section_admin 或global_admin。我进行了搜索，但没有找到任何教程告诉我如何做到这一点。

我不知道如何将角色管理集成到我的系统中。有人能帮我吗？

Controller :user.php

    class User extends Admin_Controller
            {

                public function __construct ()
                {
                    parent::__construct();
                }

                public function index ()
                {
                    // Fetch all users
                    $this->data['users'] = $this->user_m->get();

                    // Load view
                    $this->data['subview'] = 'admin/user/index';
                    $this->load->view('admin/_layout_main', $this->data);
                }

                public function edit ($id = NULL)
                {
                    // Fetch a user or set a new one
                    if ($id) {
                        $this->data['user'] = $this->user_m->get($id);
                        count($this->data['user']) || $this->data['errors'][] = 'User could not be found';
                    }
                    else {
                        $this->data['user'] = $this->user_m->get_new();
                    }

                    // Set up the form
                    $rules = $this->user_m->rules_admin;
                    $id || $rules['password']['rules'] .= '|required';
                    $this->form_validation->set_rules($rules);

                    // Process the form
                    if ($this->form_validation->run() == TRUE) {
                        $data = $this->user_m->array_from_post(array('name', 'email', 'password'));
                        $data['password'] = $this->user_m->hash($data['password']);
                        $this->user_m->save($data, $id);
                        redirect('admin/user');
                    }

                    // Load the view
                    $this->data['subview'] = 'admin/user/edit';
                    $this->load->view('admin/_layout_main', $this->data);
                }

                public function delete ($id)
                {
                    $this->user_m->delete($id);
                    redirect('admin/user');
                }

                public function login ()
                {
                    // Redirect a user if he's already logged in
                    $dashboard = 'admin/dashboard';
                    $this->user_m->loggedin() == FALSE || redirect($dashboard);

                    // Set form
                    $rules = $this->user_m->rules;
                    $this->form_validation->set_rules($rules);

                    // Process form
                    if ($this->form_validation->run() == TRUE) {
                        // We can login and redirect
                        if ($this->user_m->login() == TRUE) {
                            redirect($dashboard);
                        }
                        else {
                            $this->session->set_flashdata('error', 'That email/password combination does not exist');
                            redirect('admin/user/login', 'refresh');
                        }
                    }

                    // Load view
                    $this->data['subview'] = 'admin/user/login';
                    $this->load->view('admin/_layout_modal', $this->data);
                }

                public function logout ()
                {
                    $this->user_m->logout();
                    redirect('admin/user/login');
                }

                public function _unique_email ($str)
                {
                    // Do NOT validate if email already exists
                    // UNLESS it's the email for the current user

                    $id = $this->uri->segment(4);
                    $this->db->where('email', $this->input->post('email'));
                    !$id || $this->db->where('id !=', $id);
                    $user = $this->user_m->get();

                    if (count($user)) {
                        $this->form_validation->set_message('_unique_email', '%s should be unique');
                        return FALSE;
                    }

                    return TRUE;
                }
            }

模型 user_m.php :

                protected $_table_name = 'users';
                protected $_order_by = 'name';
                public $rules = array(
                    'email' => array(
                        'field' => 'email', 
                        'label' => 'Email', 
                        'rules' => 'trim|required|valid_email|xss_clean'
                    ), 
                    'password' => array(
                        'field' => 'password', 
                        'label' => 'Password', 
                        'rules' => 'trim|required'
                    )
                );
                public $rules_admin = array(
                    'name' => array(
                        'field' => 'name', 
                        'label' => 'Name', 
                        'rules' => 'trim|required|xss_clean'
                    ), 
                    'email' => array(
                        'field' => 'email', 
                        'label' => 'Email', 
                        'rules' => 'trim|required|valid_email|callback__unique_email|xss_clean'
                    ), 
                    'password' => array(
                        'field' => 'password', 
                        'label' => 'Password', 
                        'rules' => 'trim|matches[password_confirm]'
                    ),
                    'password_confirm' => array(
                        'field' => 'password_confirm', 
                        'label' => 'Confirm password', 
                        'rules' => 'trim|matches[password]'
                    ),
                );

                function __construct ()
                {
                    parent::__construct();
                }

                public function login ()
                {
                    $user = $this->get_by(array(
                        'email' => $this->input->post('email'),
                        'password' => $this->hash($this->input->post('password')),
                    ), TRUE);

                    if (count($user)) {
                        // Log in user
                        $data = array(
                            'name' => $user->name,
                            'email' => $user->email,
                            'id' => $user->id,
                            'loggedin' => TRUE,
                        );
                        $this->session->set_userdata($data);
                    }
                }

                public function logout ()
                {
                    $this->session->sess_destroy();
                }

                public function loggedin ()
                {
                    return (bool) $this->session->userdata('loggedin');
                }

                public function get_new(){
                    $user = new stdClass();
                    $user->name = '';
                    $user->email = '';
                    $user->password = '';
                    return $user;
                }

                public function hash ($string)
                {
                    return hash('sha512', $string . config_item('encryption_key'));
                }
            }

Answer 1

有太多方法可以将权限系统合并到您的项目中，这完全取决于您的需要。如果我正确理解了您的问题，我将为您提供有关您的案例的基本想法，我将如何做:

1. 是的，您可以向用户表添加另一个字段并将其命名为角色
2. 向您的节表添加一个 user_id 字段。这就是将用户与部分连接起来的方式。
3. 用户登录后，请检查该用户是否为section_user，如果是，则需要根据该 user_id 从数据库中提取正确的部分。
4. 如果不是，则表示它是全局管理员，然后显示所有部分。

我不确定我是否正确理解了你的问题。

请告诉我。