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mysql - 如何获得3个表列的总和

转载 作者:行者123 更新时间:2023-11-29 13:43:34 26 4
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  CREATE TABLE `table1` (
`Nameid` int(6) NOT NULL,
`name` varchar(20) default NULL,
`amount` double default NULL,
PRIMARY KEY (`Nameid`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;


INSERT INTO `table1` (`Nameid`, `name`, `amount`) VALUES
(1, 'chan', 2000),
(2, 'john', 3000),
(3, 'james', 2000);

CREATE TABLE `table2` (
`Pid` int(5) NOT NULL auto_increment,
`Nameid` int(5) default NULL,
`product` varchar(20) default NULL,
`price` double default NULL,
PRIMARY KEY (`Pid`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;


INSERT INTO `table2` (`Pid`, `Nameid`, `product`, `price`) VALUES
(1, 3, 'ghee', 400),
(2, 2, 'dhal', 100),
(3, 1, 'chenna', 150);

CREATE TABLE `table3` (
`Sid` int(5) NOT NULL,
`Nameid` int(5) default NULL,
`expence` double default NULL,
`place` varchar(25) default NULL,
PRIMARY KEY (`Sid`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;


INSERT INTO `table3` (`Sid`, `Nameid`, `expence`, `place`) VALUES
(1, 2, 280, 'Ny'),
(2, 1, 500, 'At'),
(3, 3, 600, 'ca');

我希望输出应该是这样的:

名称id|名称|产品|地点|金额|价格|费用|价格 + 费用|金额 - (价格 + 费用) |

2 |john| dhal  | Ny  | 3000 | 100 |   280 |            380|                     2620 |

1 |chan|chenna | At | 2000 | 150 | 500 | 650| 1350 |

3 |james| ghee | ca | 2000 | 400 | 600 | 1000| 1000 |

Total|------|-----|-----| 7000 | 650 | 1380 | 2030 | 4970

最佳答案

您可以使用盲 SUM()WITH ROLLUP 来实现此目的:

SELECT
table1.Nameid AS Nameid,
table1.name AS Name,
table2.product AS Product,
table3.Place AS Place,
SUM(table1.amount) AS Amount,
SUM(table2.price) AS Price,
SUM(table3.expence) AS Expence,
SUM(table2.price+table3.expence) AS Price_plus_Expence,
SUM(table1.amount-(table2.price+table3.expence)) AS Amount_minus_Price_plus_Expence
FROM
table1
INNER JOIN table2 ON table2.Namid=table1.Nameid
INNER JOIN table3 ON table3.Namid=table1.Nameid
GROUP BY table1.Nameid
WITH ROLLUP

编辑

无法在 MySQL 中创建 100% 的 OQ 输出:

  • 列名可能不包含公式:没有可行的解决方法(也没有必要:您不应使用 MySQL 客户端作为表示/格式化层)
  • 对于所有非汇总列,汇总行将包含 NULL。这可以通过类似的方法非常简单地解决。恕我直言,这也可以归结为“不要使用 MySQL 客户端作为表示层”

.

SELECT 
IFNULL(Nameid,'Total'),
IFNULL(Name, '------'),
IFNULL(Product,'-----'),
IFNULL(Place,'-----'),
Amount, Price, Expence, Price_plus_Expence, Amount_minus_Price_plus_Expence
FROM (
-- original answer query here
) AS baseview

关于mysql - 如何获得3个表列的总和,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17761261/

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