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MySQL - 嵌套选择中的引用主查询(需要嵌套)

转载 作者:行者123 更新时间:2023-11-29 13:41:30 25 4
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我一直在寻找这个问题,并且总是得到改变做事方式的答案,但没有解决一般问题,即:在嵌套 SELECT 中引用主查询变量。

我需要它是一个嵌套查询,因为数据结构非常复杂。让我们看看我需要完成的示例:

SET @teamg_id := 0;
SELECT
@teamg_id := player.team_id,
player.team_id AS player_team,
event.local_team_id AS local_team,
event.visitor_team_id AS visitor_team,
action.unique_id AS action_id,
action.player_id AS player_id,
player.name AS player_name,
playerindex.rank AS player_pos,
playerindex.ses_var_nest AS ses_var_nest
FROM
er_players player,
er_events event,
er_actions action
LEFT JOIN
(SELECT
unique_id, team_id, @pn:=@pn+1 AS rank, @teamg_id AS ses_var_nest
FROM
er_players, (SELECT @pn:=-1) p2
WHERE
team_id = @teamg_id
ORDER BY
dorsal ASC, id DESC) playerindex
ON
playerindex.unique_id = action.player_id
WHERE
action.unique_id = '1374572622'
AND player.unique_id = action.player_id
AND event.unique_id = (SELECT event_id
FROM er_analysis
WHERE unique_id = action.analysis_id)

如您所见,我需要返回该球员在其球队中的“索引”,按照查询返回的顺序(排名值),但我需要将其与球队相关进行计数,而不是整个 Players 表。

为了做到这一点,我需要在嵌套 SELECT 中引用主查询值“player.team_id” - 我尝试过但无法做到,所以我最终使用了 session 变量。

我从这个查询中得到的是 @teamg_id 在主查询中很好地存储了值,但是当传递给嵌套查询时,它的值变成 NULL:

@teamg_id  |  player_team  |  local_team  |  visitor_team  |  action_id   | player_id  |  player_name  |  player_pos  |  ses_var_nest

1374570040 | 1374570040 | 1374570040 | 1374571827 | 1374572622 | 1374570146 | Player name | NULL | NULL

我的问题是如何在嵌套查询中使用 session 变量(我认为应该有效),或者如何引用其中的主查询值。

感谢您的帮助!

编辑:这是 er_players 表的结构,这就是给我带来问题的结构。如果我说“给我‘玩家 3’的索引”,它应该给我 2 (0, 1, 2),因为这是他团队中的第三位玩家。

+------------+------------+----------+----------+--------+
| unique_id | team_id | name | position | dorsal |
+------------+------------+----------+----------+--------+
| 1374570066 | 1374570040 | Player 1 | Defense | 1 |
| 1374570034 | 1374570040 | Player 2 | Defense | 2 |
| 1374677119 | 1374571827 | Player 7 | Position | 7 |
| 1374570146 | 1374570040 | Player 3 | Attack | 5 |
+------------+------------+----------+----------+--------+

编辑 2(解决方案):由于 Kordirko 的回答和一些演奏,找到了解决方案。

 SELECT 
player.team_id AS player_team,
event.local_team_id AS local_team,
event.visitor_team_id AS visitor_team,
action.unique_id AS action_id,
action.player_id AS player_id,
player.name AS player_name,
playerindex.rank AS player_pos,
playerindex.ses_var_nest AS ses_var_nest
FROM
er_actions action
LEFT JOIN er_events event
ON event.unique_id = (SELECT event_id FROM er_analysis WHERE unique_id = action.analysis_id)
LEFT JOIN er_players player
ON player.unique_id = action.player_id
LEFT JOIN
(SELECT
unique_id, team_id, team_id AS ses_var_nest ,
case when team_id <> @lastteam
then (@pn:=-1)
end AS hander,
case when team_id <> @lastteam
then(@lastteam:=team_id)
end AS team_id_new,
@pn:=@pn+1 AS rank
FROM
er_players, (SELECT (@pn:=-1),(@lastteam:=0)) p2
ORDER BY
team_id, dorsal ASC, id DESC) playerindex
ON
playerindex.unique_id = action.player_id
AND playerindex.team_id = player.team_id /* new join condition */
WHERE
action.unique_id = '1374572622'

选择CASES后的@rank使其不两次为0,并重置选择前的@rank。否则,就变成0,而是变成每队的第二名球员。

希望有人能发现这个问题有帮助。

再次感谢 Kordirko 的宝贵时间和回答。

最佳答案

这行不通。
SELECT 子句始终在执行链的末尾进行评估,
@teamg_id 变量在嵌套子查询中将始终为 0。

尝试这个查询,它没有经过测试(我看不到你的数据,使用示例数据总是有帮助),但它可能会给出所需的结果。
我注释掉了一些部分并添加了一个连接条件。

  /*  SET @teamg_id := 0; */
SELECT
/* @teamg_id := player.team_id, */
player.team_id AS player_team,
event.local_team_id AS local_team,
event.visitor_team_id AS visitor_team,
action.unique_id AS action_id,
action.player_id AS player_id,
player.name AS player_name,
playerindex.rank AS player_pos,
playerindex.ses_var_nest AS ses_var_nest
FROM
er_players player,
er_events event,
er_actions action
LEFT JOIN
(SELECT
unique_id, team_id, @pn:=@pn+1 AS rank, team_id AS ses_var_nest ,
case when team_id <> @lastteam
then (@pn:=-1) <> (@lastteam:=team_id) end
FROM
er_players, (SELECT (@pn:=-1),(@lastteam:=0)) p2
/* WHERE
team_id = @teamg_id */
ORDER BY
team_id, dorsal ASC, id DESC) playerindex
ON
playerindex.unique_id = action.player_id
AND playerindex.team_id = player.team_id /* new join condition */
WHERE
action.unique_id = '1374572622'
AND player.unique_id = action.player_id
AND event.unique_id = (SELECT event_id
FROM er_analysis
WHERE unique_id = action.analysis_id)

关于MySQL - 嵌套选择中的引用主查询(需要嵌套),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18020184/

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