php - 返回是或否 PHP 查询

Question

我有以下查询:

    $result = query("SELECT IdUser, followingID FROM following WHERE IdUser = '%d' AND followingID = '%d'", $id, $followingID);

我想知道如果关系存在的话，如果根据 0 和 1 计数结果为"is"或“否”，我将如何返回？

Answer 1

这是一种方法:

select (case when exists (SELECT IdUser, followingID
                          FROM following
                          WHERE IdUser = '%d' AND followingID = '%d'
                         )
             then 'YES' else 'NO'
         end) as YesOrNo
, $id, $followingID