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php - 2个复选框之间的链接问题,在不应该插入数据时插入数据

转载 作者:行者123 更新时间:2023-11-29 13:39:16 24 4
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我需要列出一些输入(复选框)中的所有模式,然后我们可以选择我们想要操作的模式,以便为特定用户授予权限。

无论如何,如您所见,我明白了:

<div id="list-schemas">
<?php
foreach ($schemas as $elt) {
echo '<input type="checkbox" name="schemas[]" value="' . $elt->getSchema() . '"/>' . $elt->getSchema() . '<br />';
}
?>
</div>

然后,我还需要添加一些具有权限的复选框,我这样做了:

<div id="div-privileges">
<?php
foreach ($schemas as $elt) {
echo '<div class="list">';
echo '<label for="list">' . $elt->getSchema() . ' :</label><br />';
echo '<input type="checkbox" name="privileges[' . $elt->getSchema() . '][]" value="REVOKE"/> REVOKE ? <br />';
echo '<input type="checkbox" name="privileges[' . $elt->getSchema() . '][]" value="ALL"/> ALL PRIVILEGES ? <br />';
echo '<hr>';
echo '<input type="checkbox" name="privileges[' . $elt->getSchema() . '][]" value="SELECT"/> SELECT ? <br />';
echo '<input type="checkbox" name="privileges[' . $elt->getSchema() . '][]" value="INSERT"/> INSERT ? <br />';
echo '<input type="checkbox" name="privileges[' . $elt->getSchema() . '][]" value="UPDATE"/> UPDATE ? <br />';
echo '<input type="checkbox" name="privileges[' . $elt->getSchema() . '][]" value="DELETE"/> DELETE ? <br />';
echo '<hr>';
echo '<input type="checkbox" name="privileges[' . $elt->getSchema() . '][]" value="CREATE"/>CREATE ? <br />';
echo '</div>';
}
?>
</div>

看起来像这样:https://image.noelshack.com/fichiers/2019/37/3/1568191628-capture2.png

所以,这就是说,这是我的 UserManager.class.php 中的函数更新:

public static function update(User $newPerso){

$db = DbConnect::getDb();
$newLogin= pg_escape_string($newPerso->getLogin());
$arraySchemas=$newPerso->getSchemas();
$arrayPrivileges=$newPerso->getPrivileges();

if (isset($arraySchemas)){

foreach($arrayPrivileges as $schema => $privileges){

if (isset($arrayPrivileges)){

foreach($privileges as $privilege){

if($privilege=="REVOKE"){
pg_query("{$privilege} ALL ON ALL TABLES IN SCHEMA {$schema} FROM {$newLogin};");
}

else if($privilege=="CREATE"){
pg_query("GRANT {$privilege} ON SCHEMA {$schema} TO {$newLogin};");
}

else if($privilege=="ALL" || $privilege=="INSERT" || $privilege=="SELECT" || $privilege=="UPDATE" || $privilege=="DELETE"){
pg_query("GRANT {$privilege} ON ALL TABLES IN SCHEMA {$schema} TO {$newLogin};");
}
}
}
}
}
}

事实是,当我这样做时:https://image.noelshack.com/fichiers/2019/37/3/1568193038-capture3.png

有效,用户将在“public”上有 SELECT + INSERT,在“schematest”上有 UPDATE + DELETE

但是,

当我这样做时:https://image.noelshack.com/fichiers/2019/37/3/1568186255-capture.png

我的用户将拥有(在该示例中):

这两个模式中的所有权限...

它适用于“公共(public)”是正常的,但我如何防止“schematest”..?

最佳答案

伙计们,我添加了一个“&& in_array($schema, $arraySchemas)”

它现在似乎可以工作了,让我告诉你:

public static function update(User $newPerso){

$db = DbConnect::getDb();
$newLogin= pg_escape_string($newPerso->getLogin());
$arraySchemas=$newPerso->getSchemas();
$arrayPrivileges=$newPerso->getPrivileges();

if (isset($arraySchemas)){

foreach($arrayPrivileges as $schema => $privileges){

if (isset($arrayPrivileges) && in_array($schema, $arraySchemas)){ /****<- RIGHT HERE****/

foreach($privileges as $privilege){

if($privilege=="REVOKE"){
pg_query("{$privilege} ALL ON ALL TABLES IN SCHEMA {$schema} FROM {$newLogin};");
}

else if($privilege=="CREATE"){
pg_query("GRANT {$privilege} ON SCHEMA {$schema} TO {$newLogin};");
pg_query("GRANT USAGE ON SCHEMA {$schema} TO {$newLogin};");
}

else if($privilege=="ALL" || $privilege=="INSERT" || $privilege=="SELECT" || $privilege=="UPDATE" || $privilege=="DELETE"){
pg_query("GRANT {$privilege} ON ALL TABLES IN SCHEMA {$schema} TO {$newLogin};");
pg_query("GRANT USAGE ON SCHEMA {$schema} TO {$newLogin};");
}
}
}
}
}
}

关于php - 2个复选框之间的链接问题,在不应该插入数据时插入数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57885593/

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